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r-ruslan [8.4K]
3 years ago
7

Someone please help me with this ASAP

Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0

Answer:31

Step-by-step explanation:

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Someone help me please please someone help
Hoochie [10]
I Believe that it's -120
7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER
Dahasolnce [82]

Factor by using the rational roots test, and find that -2 is a root.

Replace X with -2 and simplify each term.

Divide the polynomial by (x+2)

The final answer becomes x = -2 and x = -1/2 +/-√3/2i

The first choice is the correct one.

5 0
3 years ago
If you plotted the points in the table and connected
castortr0y [4]

Answer:

U shaped.

Step-by-step explanation:

When x = 0 , f(x) = 6

when x =1 yf(x) = 0

when x = 2 f(x) = -2

x = 3 f(x) = 0

x = 4 f(x) = 6.

So the graphs falls from the left and rises to the right in the form of a U.

You can draw a rough graph to confirm this.

3 0
3 years ago
Russell randomly surveys seventh-graders in his school and finds that 6 of 30 attend summer camp. If there are 200 seventh-grade
Lady_Fox [76]

Answer:

40

Step-by-step explanation:

6 of 30 is the ratio 6 to 30 or 6/30.

6/30 reduces to 1/5

The survey shows that 1/5 of the students attend summer camp.

1/5 of 200 = 1/5 * 200 = 40

3 0
3 years ago
Question 3(Multiple Choice Worth 2 points)
zysi [14]

The solution to the equation are 5 or -1 after applying the quadratic formula.

<h3>What is a quadratic equation?</h3>

Any equation of the form \rm ax^2+bx+c=0  where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

It is given that:

x² - 4x² - 5 = 0

The above equation is a quadratic equation:

Using the quadratic formula:

\rm  $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plug the values in the formula:

\rm  $x=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(1)(-5)}}{2(1)}$

After solving:

x = 5 or -1

Thus, the solution to the equation is 5 or -1 after applying the quadratic formula.

Learn more about quadratic equations here:

brainly.com/question/17177510

#SPJ1

6 0
1 year ago
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