Answer:
-13/40 or -0.325
Step-by-step explanation:
Answer:
3048 x 1.04 ^3 = 3428.585474
Answer:
The x-intercept is 
The y-intercept is 
Step-by-step explanation:
Suppose you have a function f:

The x-intercept is the value of x when
.
The x-intercept is the value of y when
.
Solution
We have:


x-intercept
The x-intercept is the value of x when
. So:

*(-1)




The x-intercept is 
y-intercept
The y-intercept is the value of y when
. So:





The y-intercept is 
Answer:
Step-by-step explanation:
sinx=(opposite side)/(hypotenuse)
There really is no ‘explanation’ as that ratio IS the definition of sin.
Answer:

Step-by-step explanation:
Connect points I and K, K and M, M and I.
1. Find the area of triangles IJK, KLM and MNI:

2. Note that

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.