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3 years ago

Select the correct answer.

Mathematics

1 answer:

vovangra [49]3 years ago

6 0

Answer:

Step-by-step explanation:

think of the ratios as equivalent fractions. 2 over 14 is NOT equal to 3 over 42.

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Deepti has some boxes of crayons. Mani has two boxes more than her. Together, they have 8 boxes.

grigory [225]

Answer:

Deepti has 6 boxes of crayons

Step-by-step explanation:

they have 8 boxes together. Mani has two more than her so 8-2=6

5 0

3 years ago

Read 2 more answers

Show me the steps to solve and the solution y-2>1/2(x-2)

aev [14]

y-2>1/2(x-2) can be expanded as follows: y - 2 > (1/2)x - 1

Mult. all terms by 2 to remove the fractions:

2y - 4 > x - 2

Add 4 to both sides: 2y > x + 2

Div. both sides by 2: y > (1/2)x + 1 (answer)

4 0

4 years ago

This is used for the next few questions: The rating for the new scary movie has a scale of 0 to 10. The average response was tha

boyakko [2]

Answer:

The percentage that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8) = 83.9≅ 84 percentage

Step-by-step explanation:

Step(i):-

Mean of the Population = 8.3 points

Standard deviation of the Population = 0.5 points

Let 'X' be the random variable in normal distribution

Let X = 6.8

$Z = \frac{x-mean}{S.D} = \frac{6.8-8.3}{0.5} = -3$

Let X = 8.8

$Z = \frac{x-mean}{S.D} = \frac{8.8-8.3}{0.5} = 1$

The probability that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8) = P(-3≤Z≤1)

= P(Z≤1)- P(Z≤-3)

= 0.5 + A(1) - ( 0.5 -A(-3))

= A(1) + A(3) (∵A(-3)=A(3)

= 0.3413 +0.4986 (∵ From Normal table)

= 0.8399

Conclusion:-

The percentage that of people who gave the movie a rating between 6.8 and 8.8

P(6.8≤X≤8.8) = 83.9≅ 84 percentage

6 0

4 years ago

Which expression is equivalent to sec^2xcot^2x

Dimas [21]

Answer:

Step-by-step explanation:

Using the identities

sec x = $\frac{1}{cosx}$ , csc x = $\frac{1}{sinx}$ , cot x = $\frac{cosx}{sinx}$ , then

sec²x cot²x

= $\frac{1}{cos^2x}$ × $\frac{cos^2x}{sin^2x}$ ( cancel out cos²x )

= $\frac{1}{sin^2x}$

= csc²x → B

8 0

3 years ago

Please help.. Solve for the area of the figure below and show work.

Serhud [2]

Answer and Step-by-step explanation:

1. We can see that this kite-shape has 4 triangles in it.

The area of a triangle is as follows:

$A = \frac{bh}{2}$

Where:

b = Base (length)

h = Height

Top Right Triangle Area:

b = 9

h = 3

A = $\frac{3 * 9}{2}$

A = $\frac{27}{2}$

Bottom Right Triangle Area:

b = 9

h = 3

A = $\frac{3 * 9}{2}$

A = $\frac{27}{2}$

Top Left Triangle Area:

b = 4

h = 3

$A = \frac{4*3}{2}$

A = $\frac{12}{2}$

A = 6

Bottom Left Triangle Area:

b = 4

h = 3

$A = \frac{4*3}{2}$

A = $\frac{12}{2}$

A = 6

Now, we add all the areas together to get the area of the kite figure.

A = $\frac{27}{2}$ +

A = 27 + 12

A = 39

The area of the kite figure is 39 $m^{2}$ .

2. We have to find the area of the trapezoid.

(I'm not sure if the 9 is for the entire bottom side length)

If the bottom side length is 9, then we would use the formula:

A = $\frac{a + b}{2} h$

to find the area of the entire trapezoid.

A = $\frac{2.4 + 9}{9}$ × 8.2

A ≈ 46.74 $mi^{2}$

#teamtrees #PAW (Plant And Water)

4 0

3 years ago