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True [87]
3 years ago
9

Security is more important than freedom

Computers and Technology
1 answer:
Sidana [21]3 years ago
5 0

Answer:

I completely agree with that.

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Program: ASCII art (Python 3)1) Output this tree. 2) Below the tree (with two blank lines), output this cat. (3 pts) /\ /\ o o =
Julli [10]

The correct format for the output this tree is shown below:

(1) Output this tree

    ×

  ×××

×××××

×××××××

  ×××

(2) The correct format for the Below the tree is shown below:

Below the tree (with two blank lines), output this cat. (3 pts)

  / \        / \

     o     o

 =           =

   -   -   -

Answer:

Explanation:

We are given an Hint that:

A backslash \ in a string acts as an escape character, such as with a newline \n. So, to print an actual backslash, escape that backslash by prepending another backslash.

An Example : The following prints a single backslash: System.out.println("\\");

The main objective here is to use a Java code to interpret the above  (1) Output this tree and  (2) Below the tree.

So Using a Java code to interpret the Program: ASCII art ; we have:

public class AsciiArt {

  public static void main(String[] args) {

      // TODO Auto-generated method stub

 

      //Draw Tree

    System.out.println(" *");

      System.out.println(" ***");

      System.out.println(" *****");

      System.out.println("*******");

      System.out.println(" ***");

      //output cat

      System.out.println();

      System.out.println("/\\\t/\\");

      System.out.println(" o o");

      System.out.println(" = =")

      System.out.println(" ---");

  }

OUTPUT:

SEE THE ATTACHED FILE BELOW.

8 0
3 years ago
Determine the distance between point (x1, y1) and point (x2, y2), and assign the result to points Distance. The calculation is:
Dima020 [189]

Answer:

2 feet

Explanation:

3 0
3 years ago
In the Mouse Properties window, you can?
Levart [38]
Answer: option A. adjust the mouse's double-click speed.

You can see it in the attached file.


Download pdf
3 0
4 years ago
token is 64 bytes long (the 10-Mbps Ethernet minimum packet size), what is the average wait to receive the token on an idle netw
ikadub [295]

Given that,

Token is 64 bytes long

The average number of stations that the token must pass = 20

We need to calculate the transmission delay for token

Using formula of transmission delay

Transmission\ delay=\dfrac{token\ size}{minimum\ size}

Put the value into the formula

Transmission\ delay=\dfrac{64\ bytes}{10\ Mbps}

Transmission\ delay=\dfrac{64\times8}{10\times10^6}

Transmission\ delay=0.0000512\ sec

Transmission\ delay=5.12\times10^{-5}\ sec

We need to calculate the average wait to receive token on an idle network with 40 stations

Using formula of average wait

\text{average wait to receive token}=\text{average number of stations that the token must pass}\times transmission\ delay

Put the value into the formula

\text{average wait to receive token}=20\times5.12\times10^{-5}

\text{average wait to receive token}= 0.001024\ sec

\text{average wait to receive token}= 1.024\ ms

Hence, The average wait to receive token on an idle network with 40 stations is 1.024 ms.

8 0
4 years ago
Consider the function definition void Demo( int& intVal, float floatVal ) { intVal = intVal * 2; floatVal = float(intVal) +
Fynjy0 [20]

Answer:

myInt=40

myFloat=4.8

Explanation:

First look at the function definition .It has two arguments intVal is passed by reference while floatVal is passed by value.So the changes done on the myInt variable will be reflected on the original argument because when a variable is passed by reference the the changes are reflected on the original argument but when a variable is passed by value the function created a duplicate copy of it and work on them so changes are not reflected on the original argument.So myInt will get doubled while myFloat will remain the same.

5 0
3 years ago
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