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son4ous [18]
3 years ago
13

Find the 4th term Thank you in advance

Mathematics
2 answers:
shepuryov [24]3 years ago
7 0
B1 = 2
b2 = (b1)^2 + 1 = 2^2 + 1 = 5
b3 = (b2)^2 + 1 = 5^2 + 1 = 26

b4 = (b3)^2 + 1 = 26^2 + 1 = 676+1=<span>677</span>
kifflom [539]3 years ago
4 0
So you start off with the given information:
b_{1} = 2
b_{n} = (b_{n-1})² + 1

Since you're looking for the 4th term, that would mean that you are looking for b_{4}.
Since you know that we are looking for when n = 4, you can start with what we started off with, which is n = 1, to get to where n = 4.
When n = 1, b = 2,
when n = 2, b = 3,
when n = 3, b = 4,
when n = 4, b = 5.

So the fourth term, when n = 4, is 5. 

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