No idea because there is no image
(3,0)(0,4)
slope = (4 - 0) / (0 - 3) = -4/3
A perpendicular line will have a negative reciprocal slope. So our perpendicular line has a slope of 3/4
y = mx + b
slope(m) = 3/4
(-6,-5)....x = -6 and y = -5
now sub into the formula and find b, the y int
-5 = 3/4(-6) + b
-5 = -18/4 + b
-5 + 18/4 = b
-20/4 + 18/4 = b
-2/4 = b
so ur perpendicular line is : y = 3/4x - 2/4....or 3x - 4y = 2
and ur point (6,4) lies on the perpendicular line <===
Answer:
i hope it helps you my friend
The absolute value of a number is however many places a number is away from 0 on a number line.
a. |-15| + |-26|
15 + 26
41
b. -|-40|
-40
c. |0.5| + |-1 1/2|
0.5 + 1 1/2
0.5 = 1/2
1/2 + 1 1/2
2
