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Natali5045456 [20]
3 years ago
5

Find all real solutions to the equation. x3 + 2x2 - 6x – 12 = 0

Mathematics
1 answer:
Llana [10]3 years ago
4 0

Answer:

-6x-12 /-2x^2+x^3

Step-by-step explanation:

this question was on my math test

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Find a polynomial function f(x) of degree 3 with real coefficients that satisfies the following conditions.
frosja888 [35]

Answer:

The polynomial will be f(x) = \frac{4}{9}x(x - 2)^{2}.

Step-by-step explanation:

The three degree polynomial function f(x) has zeros at x = 0 and at x = 4 having multiplicity 2.

Therefore, (x - 0) and (x - 4)² will be factors of the polynomial f(x).

Hence, the polynomial will be f(x) = Ax(x - 4)² .............. (1), where A is any constant that we have to evaluate.

Now, given that f(5) = 20

So, from the equation (1) we have

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⇒ A = \frac{4}{9}

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3 years ago
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Step-by-step explanation:

The radius is half the diameter

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