Which method will NOT solve this equation
2 answers:
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So... let's say the amounts invested were "a" at 6% and "b" at 7.5%.
ok.. hmm what's 6% of a? well, (6/100) * a or 0.06a.
what's 7.5% of b? well, (7.5/100) * b or 0.075b.
now... we know, whatever "a" and "b" are, they total the investment of 5000 bucks, thus a + b = 5000
and the interest yielded was 337.50, thus 0.06a + 0.075b = 337.50
thus
solve for "a", to see how much was invested at 6%.
what about "b"? well, b = 5000 - a.
ok.. hmm what's 6% of a? well, (6/100) * a or 0.06a.
what's 7.5% of b? well, (7.5/100) * b or 0.075b.
now... we know, whatever "a" and "b" are, they total the investment of 5000 bucks, thus a + b = 5000
and the interest yielded was 337.50, thus 0.06a + 0.075b = 337.50
thus
solve for "a", to see how much was invested at 6%.
what about "b"? well, b = 5000 - a.