Answer:
Step-by-step explanation:
Given that 33.4% of people have sleepwalked.
Sample size n =1459
Sample favourable persons = 526
Sample proportion p = 
Sample proportion p is normal for large samples with mean = 0.334 and
std error = 
a) P(526 or more of the 1459 adults have sleepwalked.)
b) Yes, because hardly 1.4% is the probability
c) 33.4 is very less compared to the average. Either sample should be improved representing the population or population mean should be increased accordingly.
Point A: (－17＋5)÷2＝－6
Point B: (－6＋0)÷2=－3
Hope my answer helped u :)
Answer:
False
Step-by-step explanation:
The two is a positive number so it would be going up not down.
*negative number= going down positive number= going up*
Let amount invested at 6% be S
Then amount invested at 8% = 16,000 - S
We therefore have: .06(S) + .08(16,000 - S) = 1,140 .06S + 1,280 - .08S = 1,140 .06S - .08S = 1,140 - 1,280 - .02S = - 140 S, or amount invested at 6% = $ 7,000Amount invested at 8% = $16,000 - 7,000, or $ 9,000
1/a^3
The guy above me is probably also right
