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2 years ago

Find the midsegment of triangle BCD, which is parallel to BC. Label the endpoints of the midsegment as E and G.

Mathematics

1 answer:

hichkok12 [17]2 years ago

7 0

Answer:

the coordinates of E and G :E (-2 . -1) , G(1,0)

E G and BC are parallel has been shown in the explanation below

Step-by-step explanation:

The coordinate of E and G is

E (-2 . -1)

G(1,0)

To find out how E and G they are parallel to each other you have to find the slop between them

Slope formula is

m= y₂ -y₁ /x₂- x₁

y₁ = -1 , y₂ = 0 , x₁= -2 , x₂=1

then after putting values we get

m = 0-(-1) / 1-(-2)

m = 1/3

Now use formula to find the slope between B and C then

y₁ = 1 , y₂ = 3 , x₁= -3 , x₂=3

m = 3-1 / 3-(-3)

m = 1/3

so slope between B and C is also 1/3

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Y+2x=-1 y= 1/2x+4 value of x

STALIN [3.7K]

X=2

I have an image showing all work

6 0

3 years ago

Which rule describes the composition of transformations that maps ΔJKL to ΔJ"K"L"?

Vera_Pavlovna [14]

The rule that describes the composition of transformations that maps ΔJKL to ΔJ"K"L" is Rotation 0° to 90° and reflection about the x-axis.

<h3>What is the transformations rule that was used here?</h3>

A transformation is a rule that is used to manipulate the position of a point of geometric figure.

Analyzing the figure, rotation of ΔJKL through the angle 90 degrees in a counter-clockwise direction gives us ΔJ'K'L' .

ΔJ"K"L" is been gotten also using ΔJ'K'L' through the refraction of ΔJ'K'L' across the x-axis.

In this case, rule that describes the composition of transformations that maps ΔJKL to ΔJ"K"L" is Rotation 0° to 90° and reflection about the x-axis.

Learn more about Transformation from

brainly.com/question/4218767

#SPJ1

6 0

1 year ago

The winner of a 200 mile race drove his car to victory at a rate of 140.2159 mph. What was his time (to the nearest thousandth

Keith_Richards [23]

Answer: 1.43 h

Step-by-step explanation:

Velocity is $V$ is defined as the change in position (displacement) $d$ of an object in a specific time $t$ :

$V=\frac{d}{t}$

Where:

$V=140.2159 mi/h$ is the car's velocity

$d=200 mi$ is the distance the winner car traveled

$t$ is the time

Isolating $t$ :

$t=\frac{d}{V}$

Solving with the given information:

$t=\frac{200 mi}{140.2159 mi/h}$

$t=1.426 h \approx 1.43 h$ This is the winner's time

6 0

3 years ago

Which of the following points lie in the solution set to the following system of inequalities?

zheka24 [161]

The best way is to check all answers. lets check answer A first.
Take the equation y > -3x +3 and substitute 2 for x and -5 for y.
(-5)> -3(2) + 3
-5 > -6 + 3
-5 > -3
we know this is not true so A is not the answer. because it is an invalid solution.
Lets check B
(-2)>-3(5) + 3
-2 > -15 +3
-2 > -12
we know this is true so it is a valid solution Now we have to check the other equation with the same point.
y> x +2
5> (-2)+2
5> 0
we know this is true so its a valid solution.
This means B the correct answer.

5 0

3 years ago

Read 2 more answers

Use formulas to find the lateral area and surface area of the given prism. Round

tatuchka [14]

Answer:

136 m²: 188 m²

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo

My answer:

Given the information:

The height: 4m
The lenght: 13m
The width 4m

The lateral area:

As we know, the lateral area can be calculated by the following formula:

= the perimeter of the base* the height

= (13 + 4 + 13 + 4)*4

= 136 m²

The surface area:

As we know, the lateral area can be calculated by the following formula:

= The lateral area + thhe base area + the top area

= 136 + 13*4 + 13*4

= 136 + 52 + 52

= 240 m2

3 0

3 years ago