Answer:
- r = 12.5p(32 -p)
- $16 per ticket
- $3200 maximum revenue
Step-by-step explanation:
The number of tickets sold (q) at some price p is apparently ...
q = 150 + 25(20 -p)/2 = 150 +250 -12.5p
q = 12.5(32 -p)
The revenue is the product of the price and the number of tickets sold:
r = pq
r = 12.5p(32 -p) . . . . revenue equation
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The maximum of revenue will be on the line of symmetry of this quadratic function, which is halfway between the zeros at p=0 and p=32. Revenue will be maximized when ...
p = (0 +32)/2 = 16
The theater should charge $16 per ticket.
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Maximum revenue will be found by using the above revenue function with p=16.
r = 12.5(16)(32 -16) = $3200 . . . . maximum revenue
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<em>Additional comment</em>
The number of tickets sold at $16 will be ...
q = 12.5(32 -16) = 200
It might also be noted that if there are variable costs involved, maximum revenue may not correspond to maximum profit.
Answer:
-0.7
Step-by-step explanation:
First do 3.2-1.8= 1.4. So now we know that -2n=1.4. Next you solve for n to get the answer of -0.7 with your answer of the third option.
Answer:
The total comission on the sale was $375.
Step-by-step explanation:
Since the salesperson sold the car for $12,300, the total comission on the sale would be equal to the 5% of $10,000 plus the 3% of the remaining amount which would be:
Total comission=(10,000*5%)+(12,500-10000)*(3%)
Total comission=500+(2,500*3%)
Total comission=300+75
Total comission=375
According to this, the answer is that the total comission on the sale was $375.
Both have the same when simplified to its lowest point in the expression
