<h3><u>Question:</u></h3>
The second of two numbers is 4 times the first. Their sum is 45. Find the numbers
<h3><u>Answer:</u></h3>
The two numbers are 9 and 36
<h3><u>Solution:</u></h3>
Let the two numbers be "x" and "y"
Let "x" be the first number and "y" be the second number
<em><u>Given that the sum of numbers is 45</u></em>
x + y = 45 ------- eqn 1
<em><u>Also, given that, second of two numbers is 4 times the first</u></em>
second number = 4 times the first
y = 4x ------- eqn 2
<em><u>Substitute eqn 2 in eqn 1</u></em>
x + 4x = 45
5x = 45
<h3>x = 9</h3>
<em><u>Substitute x = 9 in eqn 2</u></em>
y = 4(9)
<h3>y = 36</h3>
Thus the two numbers are 9 and 36
