You would use Pythagorean theorem to help u out if u have 2 sides u should be able to do it.
1 ,3, 1
The first one is 1 the second is 3 and the last one is 1
<span>[H+] x [(CIO2)-]/[HCIO2]</span>
0,8 = 8/10 = 4/5 = 16/20...
Let's start his with some trigonometry
Cos60=x/30
X=15
Now we can use Pythagorean therom
15^2+b^2=30^2
B(y)= 25.98
