Well we already know that the 36:100 is correct because it is the starting amount, to check the 18:50 50 is half of the 100 insects so you would divide 36 by 2 which gives you half of 36 which is 18 so we can check off 18:50 as correct. Idk about the final one but the other two are correct.
Answer:
C. No, more than one output value x is assigned to the input y-value
Step-by-step explanation:
Given
х у
-3 -2
3 6
0 7
1 7
2 4
3 - 1
Required
State if the table shows x as a function of y
x being a function of y means

i.e. x represents the output while y represents the input of the function
Note that each value of y (input) must be assigned to separate values of x (output) for a function to be established
Having said;
Next step: We have to examine the x and y column
In the y column, the value 7 occurred twice (as shown below)
<em>х у
</em>
<em>0 7
</em>
<em>1 7
</em>
<em />
This implies that;
Input 7 gives output of 0 and 1.
<em>Hence, this is not a function.</em>
<em>Option C answers the question.</em>
Answer:
2x(2x²+x+1)
Dtep-by-step explanation:
f(x) = 9x³+2x²-5x+4
g(x) = 5x³-7x+4
f(x) - g(x)
= 9x³+2x²-5x+4 - (5x³-7x+4)
= 9x³+2x²-5x+4-5x³+7x-5
= 4x³+2x²+2x
= 2x(2x²+x+1)
I'm taking the liberty of editing your function <span>v = e5xey: It should be
</span>
<span>v = e^5x^ey, with " ^ " indicating exponentiation.
</span>
Did you mean e^(5x) or (e^5)x? I'll assume it's e^(5x).
The partial of v = e^(5x)e^y with respect to x is e^(5x)(5)*e^y, or 25x*e^y.
The partial of v = e^(5x)e^y with respect to y is e^(5x)e^y.