All categories

3 years ago

What is the answer I need the answer

Mathematics

1 answer:

scoray [572]3 years ago

4 0

Answer:

The correct choice is A

Step-by-step explanation:

the definition of inverse is the opposite of something or different in direction so that would mean they want you to switch what they gave you so that would mean the answer is choice A

You might be interested in

Solve 3x²-x-2=0. Please show all work.

lorasvet [3.4K]

3x²-x-2=0

Δ=1+24=25 (Δ=b²-4ac)

x₁,₂= $\frac{1(+/-)\sqrt{25} }{6}$

x₁,₂= $\frac{1(+/-)5}{6}$

x1= $\frac{1+5}{6}$ =6/6=1

x2= $\frac{1-5}{6}$ = $\frac{-2}{3}$

x1=1

x2= $\frac{-2}{3}$

3 0

4 years ago

John is driving at a constant speed of 40 miles per hour. How long does it take him to travel 50 miles?

asambeis [7]

Answer:

1 hour and 15 minutes

1.25 hr.

Step-by-step explanation:

40 miles ⇒ 1 hr.

50 miles ⇒ total hours

$\frac{50}{40}$ = 1.25 hours

7 0

3 years ago

Read 2 more answers

Find the surface area of the prism HURRY HURRY

Assoli18 [71]

Answer:

should be 192

Step-by-step explanation:

4 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

3 years ago

What is the median. I have 3 more questions that have to deal with the median.

Rom4ik [11]

Answer:

Step-by-step explanation:

Median - The middle number in a list of numbers starting from least to greatest.

Knowing this, we can start.

The first step is to rewrite all the numbers from least to greatest

15, 19, 28, 32, 43, 52, 66, 72, 72, 81

Now cross off a number from the least and greatest until there is 1 or 2 numbers left

19, 28, 32, 43, 52, 66, 72, 72

28, 32, 43, 52, 66, 72

32, 43, 52, 66

43, 52

If you are left we 1 number, that is your answer. If you are left with 2 numbers, there is an extra step

In the case that you have 2 numbers, you need to add them together, and divide by 2

43 + 52 = 95

95 ÷ 2 = 47.5

Thus 47.5 is our answer

6 0

3 years ago