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Digiron [165]
3 years ago
15

A teacher is writing a quiz. He wants the ratio of the number of easy questions to the total number of questions to be 16 font s

ize decreased by 5 : font size decreased by 5 18. If the teacher wants fewer than 16 easy questions on the​ quiz, how many easy questions should he ​write?
quick plzz
Mathematics
1 answer:
statuscvo [17]3 years ago
4 0
11 easy questions 13 hard questions
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What is the 4th term of the linear sequence below?<br> -9,-5, -1,3,7,...
Anton [14]

Answer:

The 4th term of the linear sequence = 3

Step-by-step explanation:

First term, a = -9

Common difference, d = -5 - (-9)

= -5 + 9

= 4

d = 4

The 4th term of the linear sequence = a + (n - 1)d

where,

n = 4

a + (n - 1)d

= -9 + (4 - 1)4

= -9 + (3)4

= -9 + 12

= 3

The 4th term of the linear sequence = 3

7 0
3 years ago
A force (F) applied to an object of mass m1 produces an acceleration of 3.00 m/s^2.
Lerok [7]
A) For object with mass m1,
F = m1 * 3
m1 = F/3

For object with mass m2,
F = m2 * 1
m2 = F

Ratio of m1/m2
(F/3) / F = 1/3
6 0
3 years ago
Read 2 more answers
In which number does the digit 2 have a value that is ten times as great as the value of the digit 2 in the number 135,284?
Valentin [98]

Answer: See explanation

Step-by-step explanation:

You didn't give the options but let me help out.

First and foremost, we should note that the value of the digit 2 in the number 135,284 is 200. Therefore, the value that is ten times as great as the value of the digit 2 in the number 135,284 would be:

= 10 × 200

= 2000

Therefore, the 2 must be in the thousands place. This can be seen in numbers such as:

172748.

6 0
2 years ago
Suppose that 5 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 39 cm.
vesna_86 [32]

Answer

given,

work = 5 J

spring stretch form 30 cm to 39 cm

W = \dfrac{1}{2}kx^2

x = 0.39 - 0.30 = 0.09 m

5 = \dfrac{1}{2}k\times 0.09^2

k = \dfrac{5\times 2}{0.09^2}

k = 1234.568 N/m

a) work when spring is stretched from  32 cm to 34 cm

x₂= 0.34 -0.30 = 0.04 m

x₁ = 0.32 - 0.30 = 0.02

W = \dfrac{1}{2}k(x_2^2-x_1^2)^2

W = \dfrac{1}{2}\times 1234.568 \times (0.04^2-0.02^2)^2

W = 0.741 J

b) F = k x

  25 = 1234.568 × x

     x = 0.0205 m

     x = 2.05 cm

3 0
3 years ago
In this line of ,the ratio of red circles to blue circles is 1:3 , How many more red circles would need to be added to make the
avanturin [10]

8 more red circles because if you have 9 red circles and 3 blue ones the ratio would be 9:3 and if you simplify that down to 3:1 that’s the answer. So you would need to add 8 more red circles

5 0
3 years ago
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