3y-5=20
add 5 is the next step
to obtain
3y=25
so 3rd option
Answer:
7/3
Step-by-step explanation:
f(x) =7/(x+2)
g(x) = (x + 5)^2
f(g(-4))=
First find g(-4)
g(-4) = (-4+5)^2
=(1)^2 =1
Then find f(1)
f(1)= 7/(1+2)
= 7/3
1 and 3 , they add to 4 and 3 minus 1 is 2
Answer:
1560
Step-by-step explanation:
25 x 8 x 10 - 22 x 5 x 4 = 2000 - 440 = 1560
I would use binomial distribution to answer this, since a flight being late is an independent event.
So X ~ B(16, 0.2)
The above line states that the probability of X relates to the binomial distribution with 16 trials (the 16 flights) and a 20% (0.2) chance of "success" (in this case the "success" is beimg late, which is weird because being late is not a very good thing, but the question is about being late so allow it)
So the probability of 2 flights arriving late is P(X=2) = 16C2 × 0.2^2 × 0.8^14
(The formula is basically, trialsCsuccesses × (chance of success)^(number of successes) × (chance of failure)^(total trials - successes)
The calculation will give you a probability of 0.211. And that is it :)