1st you need to fine the slope using
S = y2-y1/x2-x1
S = -6 - 3/2-2
S = -9/0
S = Undefined
when we have undefined slope the equation would be a vertical lines.
Thus the equation would be the x value of the point
Thus the equation is x = 2
Answer:
X = 27
Step-by-step explanation:
10, 20, 32, 37, 50, 60
First things first, take off 10, 20, 50, and 60.
Now, you remain with 32 and 37. Now from here it is simple.
Average of 32 and 37 = 34.83
Round 34.83 to 35
32 averaging 37 (Rounding Terms) ≈ 35
So X is 27
Answer:
Each poodle = $300
Each Cat = $150
Step-by-step explanation:
Let number of poodles be P and number of cats be C
"if he buys 3 pooples and 2 cats he will spend 1200" mathematically:
3P + 2C = 1200-------eq 1
"2 poodles and 3 cats he will spend 1050" mathematically:
2P + 3C = 1050 ------eq 2
So now we have a system of 2 equations with 2 unknowns, we'll solve by elimination
eq 1 x 3 : 3 (3P + 2C) = 3 (1200)
9P + 6C = 3600 ------ eq 3
eq 2 x 2: 2(2P + 3C) = 2(1050)
4P + 6C = 2100---------eq 4
By elimination : eq 3 - eq 4
(9P + 6C) - (4P + 6C) = 3600 - 2100
9P - 4P = 1500
5P = 1500
P = 300 (answer)
Substituting back into eq 1
3(300) + 2C = 1200
900 + 2C = 1200
2C = 1200 - 900
2C = 300
C = 150(answer)
The answer is a the first one
Answer:
The 95% confidence interval for the mean score of all such subjects is (32.033, 120.367).
Step-by-step explanation:
We have the sample standard deviation, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.039
The margin of error is:
M = T*s = 2.0639*21.4 = 44.167
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 76.2 - 44.167 = 32.033
The upper end of the interval is the sample mean added to M. So it is 76.2 + 44.167 = 120.367
The 95% confidence interval for the mean score of all such subjects is (32.033, 120.367).
