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valentina_108 [34]
3 years ago
7

Work out the size of angle X. Not dra x 164

Mathematics
1 answer:
beks73 [17]3 years ago
3 0
This would be the correct answer
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The perimeter of the original rectangle is ______
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Answer:

  • perimter of original rectangle = <u>17. 6 mm</u>
  • side length of the enlarged rectangle = <u>23. 22 mm</u>
  • perimeter of the enlarged rectangle = <u>95. 04 mm</u>

Step-by-step explanation:

<u>PERIMETER</u><u> </u><u>OF</u><u> </u><u>ORIGINAL</u><u> </u><u>RECTANGLE</u>

  • Length of original rectangle = 4.5 mm
  • Width of original rectangle = 4.3 mm

<em>perimeter = 2 × ( length + width)</em>

= 2 × ( 4.5 + 4.3)

= 2 × 8.8

= 17. 6 mm

<u>SIDE</u><u> </u><u>LENGTH</u><u> </u><u>OF</u><u> </u><u>ENLARGED</u><u> </u><u>RECTANGLE</u>

  • Width of original rectangle = 4. 5 mm
  • Width of enlarged rectangle = 24.3 mm

Enlargement factor = 24.3 / 4.5

= 5.4

  • Length of original rectangle = 4.5 mm
  • Enlargement factor = 5.4

Side length of enlarged rectangle

= original length × Enlargement factor

= 4.3 × 5.4

= 23. 22 mm

<u>PERIMTER OF ENLARGED RECTANGLE</u>

= 2 × ( enlarged ength + enlarged breadth)

= 2 × (23. 22 + 24. 3 )

= 95. 04 mm

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3 years ago
What is the difference in solving functions when giving the following information: f(x)=2 and f(2)
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<em>*Remember that y and f(x) are the same.</em>

With f(2), you are solving for the output (y), given that the input (x) is equal to 2.

With f(x) = 2, you are solving for the input (x), given that the output (y) is equal to 2.

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Select all of the following 2D shapes that may be formed by slicing a square pyramid?
ivann1987 [24]

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A and D

Step-by-step explanation:

Ok so first, if you slice parallel to the base, you can get a square.

If you slice parallel to a face, you get a triangle.

8 0
3 years ago
PLEASE HELP!!! ASAP!!!!!!!!!!!!!!! 10 POINTS
I am Lyosha [343]
1800|2\\.\ 900|2\\.\ 450|2\\.\ 225|5\\.\ \ 45|5\\.\ \ \ 9|3\\.\ \ \ 3|3\\.\ \ \ 1|\\\\1880=2\cdot2\cdot2\cdot5\cdot5\cdot3\cdot3=2^3\cdot5^2\cdot3^2\\\\Answer:\ \boxed{2^3\cdot3^2\cdot5^2}

\sqrt[3]{320}\\\\320|2\\160|2\\.\ 80|2\\.\ 40|2\\.\ 20|2\\.\ 10|2\\.\ \ 5|5\\.\ \ 1|\\\\320=2\cdot2\cdot2\cdot2\cdot2\cdo2\cdot5=2^3\cdot2^3\cdot5=2^3\cdot2^3\cdot\\\\\sqrt[3]{320}=\sqrt[3]{2^3\cdot2^3\cdot5}=\sqrt[3]{2^3}\cdot\sqrt[3]{2^3}\cdot\sqrt[3]{5}=2\cdot2\sqrt[3]{5}=4\sqrt[3]5\\\\Answer:\ \boxed{\sqrt[3]{320}=4\sqrt[3]{5}}
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3 years ago
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