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3 years ago

Which pairs of triangles can be shown to be congruent using rigid motions?

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

7 0

Two figures are congruent if and only if there exists one or more rigid motions which will map one figure onto the other.

1. Triangles ABC and MNP are not congruent.

2. Triangles ABC and EFG are not congruent

3. Triangles ABC and STU are congruent.

4. Triangles EFG and MNP are congruent.

5. Triangles EFG and STU are not congruent.

6. Triangles STU and MNP are not congruent.

Tema [17]3 years ago

7 0

Answer:

1--- not congruent

2--not congruent

3---congruent

4---congruent

5---not congruent

6---not congruent

Step-by-step explanation:

This is true because the congruent figures are equal to each other, the not congruent shapes are not congruent because they don't equal each other.(the answers are right but I am quite bad at explaining things)

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3 years ago

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2 years ago

1. What are foci? 2. What is the first step to take to write the equation of a hyperbola? 3. How do you represent parts of a hyp

Andrei [34K]

Answer: see below

Step-by-step explanation:

1) Foci is plural for Focus. Since a hyperbola has two focus points, they are referred to as foci. The foci is where the sum of the distances from any point on the curve to the foci is constant.

2) When determining the equation of a hyperbola you need the following:

a) does the hyperbola open up or to the right?

b) what is the center (h, k) of the hyperbola?

c) What is the slope of the asymptotes of the hyperbola?

3) The equation of a hyperbola is:

$\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1\qquad or\qquad \dfrac{(y-k)^2}{b^2}-\dfrac{(x-h)^2}{a^2}=1$

(h, k) is the center of the hyperbola
± b/a is the slope of the line of the asymptotes
The equation starts with the "x" if it opens to the right and "y" if it opens up

5 0

3 years ago

Phil can afford $200 a month for 5 years for a car loan. if the interest rate is 7.5 percent, how much can he afford to borrow t

madreJ [45]

200 per month for 5 years = 12,000
Phil can (at most) pay 12,000 for the car loan.
That would be the payment total.
So, how do we solve for the PRINCIPAL?
Looking at the attached formula, we see the
principal = Total - Total * ((1 +r)^-n) / r * n
where n = # of payments = 5 year * 12 months = 60 and
rate / 1.200 = 7.5/1,200 = .00625

principal = [12,000 - 12,000 * (1.00625)^-60] / .375
principal = [12,000 - 12,000 * 0.6880918239 ] / .375
principal = [12,000 - 8,257.1018863488] / .375
principal = 3,742.90 / .375
principal = 9,981.06

Source:
http://www.1728.org/loanfrm4.htm

6 0

3 years ago

Read 2 more answers