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4 years ago

Which pairs of triangles can be shown to be congruent using rigid motions?

Mathematics

2 answers:

andreyandreev [35.5K]4 years ago

7 0

Two figures are congruent if and only if there exists one or more rigid motions which will map one figure onto the other.

1. Triangles ABC and MNP are not congruent.

2. Triangles ABC and EFG are not congruent

3. Triangles ABC and STU are congruent.

4. Triangles EFG and MNP are congruent.

5. Triangles EFG and STU are not congruent.

6. Triangles STU and MNP are not congruent.

Tema [17]4 years ago

7 0

Answer:

1--- not congruent

2--not congruent

3---congruent

4---congruent

5---not congruent

6---not congruent

Step-by-step explanation:

This is true because the congruent figures are equal to each other, the not congruent shapes are not congruent because they don't equal each other.(the answers are right but I am quite bad at explaining things)

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Answer:

$(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

Step-by-step explanation:

The reference angle is the angle that the given angle makes with the x-axis.

For an ordered pair to share the same reference angle, the x and y coordinates must be the same or a factor of each other.

From the given options:

$(A)\left(-\dfrac{\sqrt{3} }{2} ,-\dfrac{1 }{2}\right)$ and \left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)\\\\(B)\left(\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(-\dfrac{\sqrt{3} }{2}, \dfrac{1 }{2}\right)\\\\(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)\\\\(D)\left(\dfrac{\sqrt{3} }{2},\dfrac{1 }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

We observe that only the pair in option C has the same x and y coordinate with the second set of points being a negative factor of the first term. Therefore, they have the same reference angle.

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Answer:

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Step-by-step explanation:

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Answer:

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