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Brrunno [24]
3 years ago
5

What's the answer to 4n - 9 = -9

Mathematics
2 answers:
aksik [14]3 years ago
8 0
Hello!

You solve this algebraically

4n - 9 = -9

Add 9 to both sides

4n = 0

Divide both sides by 4

n = 0

The answer is 0

Hope this helps!
ratelena [41]3 years ago
8 0
The answer you are looking for is "n = 0".

This can be found by adding 9 to each side, which would leave you with "4n = 0". To get "n" by itself, you'd then divide both sides by 4. "N" in this case would equal 0, because 0 divided by any number, will always be 0.

To check this answer, you could replace "n" with 0, and solve the left side. This would leave you with "-9 = -9", meaning the answer is correct.

I hope this helps!
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find all local maximum and minimum points by the second derivative test when possible y=2+3×+3 (b) y=6×+sin3×​
inessss [21]

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Step-by-step explanation:

Given a function f, whose derivatives are f' and f'', a value x is a critical point if f'(x) =0. A value x is a minimum of f if it is a critical point and f''(x) >0 and it is maximum if f''(x)<0. We will perfom the following steps:

1. Calculate the derivative f'.

2. Solve f'(x) =0.

3. Determine if the x value found in 2 is a minimum or a maximum using f''.

Recall the following properties of derivatives

(\sin(x)) ' = \cos(x)

(\cos(x))' = -\sin(x)

(cf(x))' = cf'(x) where c is a constant.

(x^n)' = nx^{n-1}

(f+g)' = f'+g' where f,g are differentiable.

(c)' =0 where c is a constant.

(f(g(x))' = f'(g(x)) \cdot g'(x) (chain rule)

Case 1: f(x) = 2+3x+3.

Using the properties from above, we have

1. f'(x) = 0+3+0 = 3

2. The equation f'(x)=0 where f'(x) = 3 has no solution.

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3. Based on the previous result, f has no maximum nor minimum.

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