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Lyrx [107]
3 years ago
6

To approach a runway, a pilot of a small plane must begin a 10 degrees descent starting from a height of 1983 feet. To the neare

st tenth of a mile , how many miles from the runway is the airplane at the start of it's descent?
Trigonometry
Mathematics
1 answer:
Marizza181 [45]3 years ago
4 0
Tan (10 degrees) = 1983 / distance
distance = 1983 / tan (10 degrees)
distance = 1983 / 0.17633
<span><span><span>distance = 11,246</span> feet

11,246 / 5,280 = 2.13 miles</span> </span>

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Solve x/2 + y/3 = 1 for x
denis23 [38]

Answer:

x = - \frac{2y}{3} + 2

Step-by-step explanation:

Solve for x by simplifying both sides of the equation , isolating the variable.

Hope this helped you, Also please let me know if anything is unclear or wrong!

4 0
3 years ago
Read 2 more answers
En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand
Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Donde:

F_{1} - Fuerza experimentada por el elefante, medida en newtons.

F_{2} - Fuerza aplicada sobre el plato pequeño, medida en newtons.

A_{1} - Área del plato grande, medida en metros cuadrados.

A_{2} - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g (2)

Donde:

D_{1} - Diámetro del plato grande, medido en centímetros.

D_{2} - Diámetro del plato pequeño, medido en centímetros.

m - Masa del elefante, medida en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que D_{1} = 0.75\,m, D_{2} = 0.13\,m, m = 2900\,kg y g = 9.807\,\frac{m}{s^{2}}, entonces la fuerza a aplicar al émbolo pequeño es:

F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{2} = 854.473\,N

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0
3 years ago
A rectangular lot is 115 yards long and 70 yards wide give the length and width of another rectangle lot that has the same perim
s2008m [1.1K]

Answer:165 length 20 width

3 0
3 years ago
Find the sales tax for a lawnmower that cost 265.00 at a 6% tax rate?
maksim [4K]

Answer:

C. $15.90

Step-by-step explanation:

6% to a decimal is 0.06. Multiply 265.00 * 0.06 to get the answer.

3 0
3 years ago
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The cost for 7 dance lessons is 82$. The cost for 11 lessons is 122$. Write and solve an equation to find the cost of 4 lessons
Juliette [100K]

Answer:

$52

Step-by-step explanation:

Using the equation

y=mx+c

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11x-7x=122-82

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To get c

82=7(10)+c

82-70=c

c=12

For 4 lessons

y=10(4)+12=52

6 0
3 years ago
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