What is 27/48 in lowest terms?

The average mass of an ant is approximately 3 × 10 − 3 grams. The average mass of a giraffe is approximately 2 × 10 3 kilograms.

Vika [28.1K]

Given that average mass of an ant $= 3 \times 10^{-3}$ grams.

Given that average mass of a giraffe $= 2 \times 10^{3}$ Kilograms.

Now we have to find about how many times more mass does a giraffe have than an ant. Before carring out any comparision, we must make both units equal.

Like convert kilogram into gram or gram into kilogram.

I'm going to convert kilogram into gram using formula

1 Kg = 1000 g

So the average mass of a giraffe $= 2 \times 10^{3} *10^3$ grams.

Now we just need to divide mass of giraffe by mass of ant to find the answer.

$\frac{2 \times 10^{3} *10^3 }{3 \times 10^{-3} }$

$= \frac{2 \times 10^{3} *10^3 *10^{3}}{3 }$

$= \frac{2 \times 10^{3+3+3}}{3 }$

$= \frac{2 \times 10^9}{3 }$

$= \frac{2}{3 } \times 10^9$

=666666666.667

Hence final answer is $\frac{2}{3 } \times 10^9$ which is approx 666666666.667.

3 0

2 years ago

An average person in the United States throws away 4.5 × 10² g of trash per day. In 2013, there were about 3.2×1063.2×106 people

Mashcka [7]

Well, Since every 1 person throws away 4.5 × 10² g trash each day (365 days in each year), You would times 3.2×1063.2×106 by the 4.5 × 10² g to get how much trash was thrown away each day and then times that by 365 to figure how much trash was thrown away the entire year

8 0

2 years ago

Niall owes $187 to his cousin. However, he doesn't have any money right now. He hopes to earn some money by painting a house. He

Alla [95]

The equation would be 34 x 2x-187= y.

8 0

2 years ago

Read 2 more answers

An investment services company experienced dramatic growth in the last two decades. The following models for the company's reven

zlopas [31]

Answer: a) 138.32 and b) 35 years approx.

Step-by-step explanation:

Since we have given that

$R(t)=21.4e^{0.13t}\\\\C(t)=18.6e^{0.13t}$

So, Profit is given by

$Profit=R(t)-C(t)\\\\Profit=21.4e^{0.13t}-18.6e^{0.13t}\\\\Profit=e^{0.13t}(21.4-18.6)\\\\Profit=2.8e^{0.13t}$

Difference in years of 1990 and 2020=30

So, Profit becomes :

$P(30)=2.8e^{0.13\times 30}\\\\P(30)=2.8\times 49.40\\\\P(30)=138.32$

(b) How long before the profit found in part (a) is predicted to double? (Round your answer to the nearest whole number.) years after 1990.

So, profit doubles , we get :

$138.32\times 2=2.8e^{0.13t}\\\\276.65=2.8e^{0.13t}\\\\\dfrac{276.65}{2.8}=e^{0.13t}\\\\98.80=e^[0.13t}\\\\\ln 98.80=0.13t\\\\4.593=0.13t\\\\\dfrac{4..593}{0.13}=t\\\\35.33=t$

Hence, a) 138.32 and b) 35 years approx.

6 0

2 years ago

What is the solution to the inequality?

Alexxx [7]

Answer:

Oc. x>11

Step-by-step explanation:

Subtract 4 from 4 which will give you 0, then subtract 4 from 15 which should give you 11. x is still greater than 11. You don't switch the signs unless you're dividing or multiplying by a negative number. Hope this helps.

4 0

2 years ago