Answer:
c=13 and a=20
Step-by-step explanation:
Here you need to use the Pythagoras theorem :
c²=a² + b²
c = √a² + b²
c = √(12)²+(5)²
c= √144+25
c = √169
c = 13
2) c²=a²+b²
b= √c²-b²
b= √(29)²-(21)²
b = √400
b = 20
In 2 you change your formula just so that it can be easier and just calculate your length straight forward but you can also just do it in the original equation
No. A square has equal sides that are perpendicular and parallel. I'm guessing this room resembles some other figure.
The simplest way to solve this is to notice that letting t = 8/3 will let the term (3t-8) = 0. Substituting this will make v(t) = 2. Then we check which graphs pass through (8/3, 2). Only the second and third graphs do.
Next, we look at the behavior of the graph as t increases. Based on the equation, as t increases, (3t-8)^3 increases as well, so v(t) will increase as well. This is shown by the second graph, in which v(t) increases as t increases.
Answer:
2
Step-by-step explanation:
