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ALGEBRA II
Ingrid H.
asked • 04/02/20
The sum of three numbers is 126 . The third number is 3 times the first. The second number is 6 more than the first. What are the numbers?
The sum of three numbers is 126
. The third number is 3
times the first. The second number is 6
more than the first. What are the numbers?
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Mackenzie K. answered • 04/02/20
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Lets define a=1st number, b=2nd number, and c=3rd number
We know that a+b+c=126
We also know that the second number is 6 more than the first, so we can represent this as b=a+6
We also know that the third number is 3 times the first which can be represented as c=3a
We can plug these new values into our original equation and get:
a+(a+6)+(3a)=126
2a+6+3a=126 COMBINE LIKE TERMS
5a+6=126
5a=120
a=24
Our first number is 24.
Our second number is 6 more than our first number, so the second number is 24+6=30
Our third number is 3 times the first number, so the third number is 3(24)=72
We can check by plugging these numbers in for a, b, and c in our original equation
a+b+c=126
24+30=72=126
126=126
