Solution: Because we are given, each month the number of members gets triple, that means each month we can multiply by 3 to the number of members of previous month.

For first month, we would multiply 1,000 by 3.

For second month, we would multiply 1,000 by 3 *3.

For second month, we would multiply 1,000 by 3*3*3.

Each month one factor of 3 is being increasing.

We could write those 3's as exponents of 3.

Like $1000*3 = 1000*3^1$

$1000 * 3^2.$

$1000 * 3^3.$

As many months as many 3's are there.

So, the exponent of 3 is represnts the number of months.

Let us take a variable for number of month by n.

So, we could setup an equation for number of members m belongs to site on a particular month n as

$m= 1000 (3)^n$

This is our final equation.

7 0

3 years ago

How many solutions does 2.3y+3.2-y=2.1+1.3y+1.1 have?

jeka57 [31]

1.3y +3.2 = 1.3y +3.2

we notice that both sides of the equation are identical. So substitute y with any value and the equation would still be correct.

y has infinite solutions.

6 0

3 years ago