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PilotLPTM [1.2K]
3 years ago
11

The area of a playground is 2,400 square yards, and the width is 40 yards. What is the length of the playground? PLEASE HELP

Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0
The answer you are looking for is 60 yards!
You can use the formula x*y=z
Making 40*y=2400
Do 2400/40= 60
40*60=2400
Making 60 your length of the playground!
I hope this helps!
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Calculate the average rate of change for the function f(x) = x4 + 3x3 - 5x2 + 2x - 2, from x = -1 to x = 1
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In interval <a, b>  the average rate of change the function you count from this formula:
x=\frac{f(b)-f(a)}{b-a} \qquad b>a
Here you've got a=-1 and b=1:
f(a)=f(-1)=(-1)^4+3 \cdot (-1)^3 - 5 \cdot (-1)^2 +2 \cdot (-1)-2= \\ = 1-3-5-2-2=-11 \\ \\ f(b)=f(1)=1^4+3 \cdot 1^4 - 5 \cdot 1^2 + 2 \cdot 1 -2=1+3-5+2-2=-1 \\ \\ \hbox{So average rate of change this function is:} \\ \\ x= \frac{-1+11}{1+1}=\frac{10}{2}=5
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What is the degree of the monomial? 7m 6 n 5
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Anyone wanna help me out??
Burka [1]

Answer:

  • 6955 ft

Step-by-step explanation:

  • <em>Refer to attached. Point J, segment BJ and angle measures added.</em>

<u>Step 1, find BJ</u>

  • BJ / AB = sin 20° ⇒ BJ = AB sin 20° ⇒ BJ = 600 sin 20° ≈ 205.2 ft

<u>Step 2, find BP</u>

  • BJ/BP = cos 75° ⇒ BP = BJ / cos 75° ⇒ BP = 205.2/cos 75° ≈ 792.8 ft

<u>Step 3, find PQ</u>

  • PQ/BP = sin 35° ⇒ PQ = BP sin 35° ⇒ PQ = 792.8 sin 35° ≈ 454.7 ft

<u>Step 4, find the elevation of peak P</u>

  • Height above sea level = 6500 + 454.7 ≈ 6955 ft (rounded)

5 0
3 years ago
A rock is dropped from a height of 100 feet. Calculate the time between when the rock was dropped and when it landed. If we choo
andre [41]

The time it takes between when the rock was dropped and when it landed is 1.33 seconds.

<h3>What is the time it takes for the rock to land?</h3>

The time it takes the rock to land on the ground from where it is dropped can be determined by using the function given.

The height of the function when it hits the ground will be zero, so the function can be written as:

\mathbf{h(t) =36t^2 -64}

\mathbf{0 =36t^2 -64}

64 = 36t²

\mathbf{t^2 = \dfrac{64}{36}}

t² =1.778

t = \sqrt{1.778}

t = 1.333 seconds

Learn more about calculating the time of a function here:

brainly.com/question/26898697

#SPJ1

6 0
2 years ago
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