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Arturiano [62]
3 years ago
10

1. solve the inequality 8x ≤ 48

Mathematics
2 answers:
Korvikt [17]3 years ago
8 0

Answer:

Part 1: A. x ≤ 6

Part 2: B. x > 13

Part 3: C. x ≤ 42

Part 4: Option C and D

Step-by-step explanation:

Given the questions of inequality in parts we have to solve these inequality.

Part 1:  8x ≤ 48

Dividing by 8 on both sides, we get

\frac{8x}{8}\leq \frac{48}{8}

x\leq 6

Option A is correct.

Part 2:  10 + x > 23

Subtracting 10 from both sides, we get

10+x-10> 23-10

x> 13

Option B is correct.

Part 3: x - 14 ≤ 28

Adding 14 on both sides, we get

x-14+14\leq 28+14

x\leq 42

Option C is correct.

Part 4: x - 4 ≥ 0

we have to choose the values which can be submitted for x to make the inequality x - 4 ≥ 0 true

Adding 4 on both sides

x - 4+4 ≥ 0+4

x ≥ 4

Since 4 and 18 are only two numbers ≥ 4.

Hence, the correct option is C and D

bonufazy [111]3 years ago
5 0
1.8x≤48
x≤6 (A)
2.10+x>23
x>13(B)
3.x-14≤28
x≤42(C)
4.There are no y in the inequality
5.x-4≥0
4=4,18≥4
So C and D are the answer
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Answers to numbers 2 and 3
BARSIC [14]
For both of them you just make them into fraction.
For #2
\frac{36}{120}
and then you simplify it
36. ÷12 3
-----. =. --------
120. ÷12 10
After this you want to change the fraction to a percentage.Percentage are out of 100

so you simply will multiply by 10 to the top and bottom
3. 30
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10. 100

The answer is 30%

For number #3
you simply put 63 over 240
63
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240
63  \div 3= 21
240 \div 3 = 80
\frac{21}{80}
21
----
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is that answer because it can't be simplified
after that


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