M(x)=−(x−5) 2 +25m, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 5, right parenthesis, squ
Aleksandr [31]
Answer:
25
Step-by-step explanation:
Given the function that represents the amount of mosquitoes as;
M(x) = -(x-5)² + 25
To get the maximum mosquitoes possible, we need to first find x;
At the maximum dM/dx = 0
dM//dx = -2(x-5)
0 = -2(x-5)
-2(x-5) = 0
-2x + 10 = 0
-2x = -10
x = 10/2
x = 5
Substitute x = 5 into the function;
M(5) = −(5−5)² +25
M(5) = 0+25
M(5) = 25
Hence the maximum number of mosquitoes is 25
Answer:
Minimum value of function
is 63 occurs at point (3,6).
Step-by-step explanation:
To minimize :

Subject to constraints:

Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line
Eq (2) is in green in figure attached and region satisfying (2) is below the green line
Considering
, corresponding coordinates point to draw line are (0,9) and (9,0).
Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line
Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)
Now calculate the value of function to be minimized at each of these points.

at A(0,9)

at B(3,9)

at C(3,6)

Minimum value of function
is 63 occurs at point C (3,6).
So the first step is to have a line segment.
Put your compass on one of the points and extend the compass to be slightly more than half. Just a bit over half.
Mark a small curvy line above your segment and on the bottom at that length.
Now pick up the compass, don't change the length of extension, and put it on the other point of your segment.
Mark above and below your segment like before so it can intersect.
draw a line through the two intersections.
I hope I answered your question.
Answer:
It will take 6.118 minutes to fill up the pool to a depth of 20 cm
Step-by-step explanation:
The first step is to calculate the volume of the wading pool.
we will assume it is a cylinder, hence the volume will be = 
<em>Where r= radius of the pool = 115/2 = 57.5cm</em>
<em>h = depth of the pool =20 cm</em>
The volume of the pool will be 
We are filling a pool of 208,000cm ^{3} at the rate of 34000cm^3, cubed per minute.
To get the time it will take to fill up the pool, we will have to divide as follows:
208,000cm ^{3} / 34000cm^3 =6.118 minutes
Therefore it will take 6.118 minutes to fill up the pool to a depth of 20 cm
So you can choose any number from 11 to 19.
I'll choose 11 for now.
Then you write, 11, the number, and then spell it out, eleven.
To show how many tens and ones, you can make a place value chart. You would make two boxes, the first one for tens and the other for ones.
You would put a 1 in the tens place and a 1 in the ones place.
I hope this helps!