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FinnZ [79.3K]
3 years ago
12

Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.

Mathematics
1 answer:
USPshnik [31]3 years ago
7 0

Answer:

x = -0.95

Step-by-step explanation:

2e^-x+1 -5 = 9

2e^-x+1 = 9+5 = 14

e^-x+1 = 14/2 = 7

e^-x+1 =7

-x+1 = In 7 = 1.95

-x+1 = 1.95

x = 1 - 1.95 = -0.95

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How many times larger than (6 - 4) is (6 - 4) × 5?
tresset_1 [31]

Answer:

5 times bigger

Step-by-step explanation:

(6-4) = 2

(6-4) x 5 = 10

4 0
2 years ago
If the output number y is -52 (y=5x-2) what is the input number? SHOW WORK
nordsb [41]

Answer:

the input number is -10

Step-by-step explanation:

output is always y

input is always x

so instead of y, put -52

-52=5x-2  add 2 to each side to ger 5x by itself

-50=5x     divide both sides by 5 to get x by itself

-10=x

x is the input so the input is -10

8 0
3 years ago
What is the maximum number of possible solutions for the system shown below?
Fudgin [204]

Answer:

2

Step-by-step explanation:

The first equation is that of a an ellipse. The second equation is that of a line.

Attached is the graphs of both of these equations.

<em>If you think about it, there can only be 2 possible ways of solutions (intersection points) of an ellipse and a line.</em>

<em>1. The line will not intersect the ellipse at all, so no solution</em>

<em>2. The line will intersect the ellipse at 2 points maximum</em>

<em />

So, we can clearly see from the reasoning that the maximum number of possible solutions would be 2. The graph attached confirms this as well.

8 0
3 years ago
Read 2 more answers
Which of the following graphs would you use if you wanted viewers to see individual data points?
Arturiano [62]
I would either use a histogram or a frequency chart, but histogram is easier and neater 
7 0
3 years ago
Late work 4 physics
Oliga [24]

Answer:

Step-by-step explanation:

problem 4

Velocity is +2.0m/s and constant acceleration is -0.5m/s^2

For every second the velocity drop by 0.5 m/s, so after 2 seconds the velocity is  1 m/s.

problem 5

Accelerate from rest to 28m/s means go from 0 to 28m/s so with

a constant acceleration of 5.5 m/s^2 it will take 5.09 second

7 0
3 years ago
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