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Oxana [17]
3 years ago
14

Solve for q. 3 (q+4/3) = 2

Mathematics
2 answers:
TiliK225 [7]3 years ago
7 0
3(q+4/3)=2
Use the distributive property:
3q+4=2
3q=-2
q=-2/3
Check your answer:
3(-2/3+4/3)=2
3(2/3)=2
2=2
Hope this helps. 
Setler [38]3 years ago
4 0

°° Let's see -

Let's start by solving your equation step-by-step. I'll include steps :)

Rewrite the equation:

3 (q + 4/3) = 2


1) Simplify both sides of the equation.

3 (q + 4/3) = 2

Simplify the equation - With steps!

(3) (q) + (3) (4/3) = 2 (Distribute)

3q + 4 = 2


2) Subtract 4 from both sides.

3q + 4 - 4 = 2 - 4


3) Divide both sides by 3.

3q/3 = -2/3

q = -2/3

Final Answer:

q = -2/3

↑   ↑   ↑  Hope this helps! :D

_____________________________________________________________

Want to check your work? Simply substitute -2/3 for the variable and then just complete the equation USING PEMDAS! Never forget about PEMDAS!


(In math, PEMDAS will always be your best friend)

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Factor: g^2 - 12gh + 35h^2
Kipish [7]
(g-5h)(g-7h). Hope this helps!
4 0
4 years ago
Help me please and thanks
ladessa [460]
Keep in mind that the graph counts in twos.

The factored form of the polynomial deals with the zeros in the graph. Identify the zeros in the graph:

Zeros at:
x = -4, (-4,0)
x = 4, (4,0)

Both values must be inputted into the answer and result in an output of 0, so the answer will be C. (x+4)(x-4).

Proof:

x = 4:
(4+4) \times (4-4) = 8 \times 0 = 0

x = -4
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8 0
3 years ago
Which equation shows a valid, practical step in solving
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For this case we have the following equation:

\sqrt [4] {2x-8} + \sqrt [4] {2x + 8} = 0

If we subtract both sides of the equation \sqrt [4] {2x + 8} we have:

\sqrt [4] {2x-8} = - \sqrt [4] {2x + 8}

To eliminate the radical we raise both sides of the equation to the fourth power:

(\sqrt [4] {2x-8}) ^ 4 = (- \sqrt [4] {2x + 8}) ^ 4

Answer:

Option D

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Can I get help please ​
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Answer:

x > -3.2

Step-by-step explanation:

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