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kozerog [31]
3 years ago
7

Of the 81 people who answered "yes" to a question, 6 were male. of the 70 people that answered "no" to the question, 6 were male

. if one person is selected at random from the group, what is the probability that the person answered "yes" or was male?
Mathematics
1 answer:
Stells [14]3 years ago
7 0

there is about a 4% chance that they answer yes and about an 8% chance they are male.

Yes probability- 6/151≈.039 which rounds to .4 or 4%

Male probability- 12/151≈.079 which rounds to .8 or 8%

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I really need help on this one
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Part A:

Given that Rachel is planning a wedding for 100 to 250 people, the <span>inequality in terms of p people that describes how many people Rachel plans to invite is given by:

100 ≤ p ≤ 250



Part B:

Given that the </span>caterer charges $20 per person, plus a flat fee of $200,<span> the </span><span>inequality that shows how much the caterer will charge in terms of p is given by:

20(100) + 200 ≤ 20p + 200 ≤ 20(250) + 200
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Part C:

<span>The range of catering fees (C) that Rachel is considering is given by:

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4 0
4 years ago
If f(x)= <br><img src="https://tex.z-dn.net/?f=x%20-%20%7Bx%7D%5E%7B2%7D%20" id="TexFormula1" title="x - {x}^{2} " alt="x - {x}^
astra-53 [7]

Answer:

f(2+h)=-(h+2/3)^2+1/4

f(x+h)=-(x+h-1/2)^2+1/4

Step-by-step explanation:

1. f(2+h)=(2+h)-(2+h)^2=2+h-4-4h-h^2=-h^2-3h-2=-(h^2+3h+2)

=-(h+2/3)^2+1/4

2. Let (x+h)=a, then rewrite the equation into f(a)=a-a^2.

a-a^2=-(a^2-a)=-[(a-1/2)^2-1/4]=-(a-1/2)^2+1/4.

Insert a=x+h, f(x+h)=-(x+h-1/2)^2+1/4

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3 years ago
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The first thing that comes to mind that an absolute value cannot have a nagative output, in other words, if you have an function that is equal to a negative number, then there is no solution.

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