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3 years ago

Why is 64 the opposite of-4 with the power of 3? Talking integers.

Mathematics

1 answer:

worty [1.4K]3 years ago

7 0

-4^3 is -64. so 64 is the opposite of -64

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The weights of soy patties sold by Veggie Burgers Delight are normally distributed. A random sample of 15 patties yields a mean

Elden [556K]

Answer:

$t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549$

Step-by-step explanation:

Data given and notation

$\bar X=3.8$ represent the sample mean

$s=0.5$ represent the sample standard deviation for the sample

$n=15$ sample size

$\mu_o =4$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean weight is less than 4 ounces, the system of hypothesis would be:

Null hypothesis: $\mu \geq 68$

Alternative hypothesis: $\mu < 4$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549$

3 0

3 years ago

Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a downward sloped line crossing the y

anastassius [24]

Answer: The right hand limit is 4

-------------------------------

Start on the right side of the value x = 2. In other words, start at some value larger than 2, say x = 4. Starting at x = 4, move closer to x = 2. Move as close as you can. The closer x gets to 2, the closer y gets to 4. You'll never actually get to x = 2 or y = 4 because of the hole. However, the right-hand limiting value is 4 assuming you can keep getting closer and closer.

Note: if you approach x = 2 from the left side, you arrive at a different y value So this suggests that overall, the limit at x = 2 doesn't exist. But the right hand limit (RHL) does exist as described above.

7 0

4 years ago

lorena lifeguards at a lap pool that is 25 yards long, 10 ards wide, and 2 yards deep. There is a drain around he entire top edg

Varvara68 [4.7K]

The true statements about the pool are

The drain is best measured using perimeter
The area of the cover is 250 square yards
One edge of the pool measures 10 yd

<h3>How to determine true statements?</h3>

The given parameters are:

Length = 25 yards
Width = 10 yards
Depth = 2 yards

To measure the drain, we simply calculate the perimeter of the edge of the pool.

This means that (a) is correct

When the volume is calculated, the unit is cubic yard or yd³.

This means that (b) is wrong

The area of the cover is:

Area = Length * Width

This gives

Area = 25 yards * 10 yards

Evaluate

Area = 250 square yards

This means that (c) is correct

The length of the drain is calculated as:

Perimeter = 2 *(Length + Width)

This gives

Perimeter = 2 * (25 + 10)

Evaluate

Perimeter = 70

This means that (d) is wrong

Lastly (e) is correct, because the width of pool is 10 yards

Read more about perimeter and volume at:

brainly.com/question/15465114

#SPJ1

7 0

2 years ago

The ratio of apples to bananas is 1 to 3. The ratio of peaches to bananas is 3 to 2. What is the ratio of apples to peaches?

Ksivusya [100]

Answer:

The ratio of apples to peaches is 2 to 9.

Step-by-step explanation:

For every 1 apple, there are 3 bananas.

For every 3 peaches, there are 2 bananas.

To compare apples to peaches, we need to make the bananas in each of the proportions equal.

(1 apple = 3 bananas ) x 2 --> 2 apples= 6 bananas

(3 peaches = 2 bananas) x 3 --> 9 peaches= 6 bananas

Now that the bananas are equal and the other fruits are proportionate to the number of bananas, we can see that for every 2 apples there are 9 peaches.

3 0

3 years ago

Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of

kifflom [539]

Looks like we have

$\vec F(x,y,z)=z^2x\,\vec\imath+\left(\dfrac{y^3}3+\sin z\right)\,\vec\jmath+(x^2z+y^2)\,\vec k$

which has divergence

$\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(z^2x)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial z}=z^2+y^2+x^2$

By the divergence theorem, the integral of $\vec F$ across $S$ is equal to the integral of $\nabla\cdot\vec F$ over $R$ , where $R$ is the region enclosed by $S$ . Of course, $S$ is not a closed surface, but we can make it so by closing off the hemisphere $S$ by attaching it to the disk $x^2+y^2\le1$ (call it $D$ ) so that $R$ has boundary $S\cup D$ .

Then by the divergence theorem,

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(x^2+y^2+z^2)\,\mathrm dV$

Compute the integral in spherical coordinates, setting

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}\implies\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

so that the integral is

$\displaystyle\iiint_R(x^2+y^2+z^2)\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^1\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{2\pi}5$

The integral of $\vec F$ across $S\cup D$ is equal to the integral of $\vec F$ across $S$ plus the integral across $D$ (without outward orientation, so that

$\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\frac{2\pi}5-\iint_D\vec F\cdot\mathrm d\vec S$

Parameterize $D$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

with $0\le u\le1$ and $0\le v\le2\pi$ . Take the normal vector to $D$ to be

$\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=-u\,\vec k$

Then we have

$\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^1\left(\frac{u^3}3\sin^3v\,\vec\jmath+u^2\sin^2v\,\vec k\right)\times(-u\,\vec k)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{2\pi}\int_0^1u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac\pi4$

Finally,

$\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\frac{2\pi}5-\left(-\frac\pi4\right)=\boxed{\frac{13\pi}{20}}$

6 0

4 years ago