All categories

2 years ago

[2P-3.) ^2+(2P+3)^2

Mathematics

1 answer:

WINSTONCH [101]2 years ago

4 0

Answer:

[2P-3.) ^2+(2P+3)^2[2P-3.) ^2+(2P+3)^2[2P-3.) ^2+(2P+3)^2

You might be interested in

0.92 repeating as a fraction<br> (0.9222222222222222222........)

Scrat [10]

Answer:

0.9222222222222222/1

Step-by-step explanation:

8 0

3 years ago

Will give brainliest or whatever it’s called

Softa [21]

C is the right answer.

hope it helps...

8 0

1 year ago

Read 2 more answers

If a fair-number cube with sides numbered from 1 to 6 is tossed 240 times, approximately how many times would the fair-number cu

LenKa [72]

It wouls be greater 50times

8 0

2 years ago

PLEASE I NEED HELP! How do you find y?

myrzilka [38]

In this example, y is equal to 8.

In order to find this, first note that the two x value expressions create a straight line. That means when we add them together they will equal 180. this will give us a value for x.

x + 10 + 10x - 61 = 180

11x - 51 = 180

11x = 231

x = 21

Now that we have the value of x, we can do the same for the straight line created by the x + 10 angle and the 18y + 5 angle.

x + 10 + 18y + 5 = 180

(21) + 10 + 18y + 5 = 180

36 + 18y = 180

18y = 144

y = 8

4 0

3 years ago

Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .

Hope this wasn't too confusing! I'll answer any questions.

8 0

2 years ago

Read 2 more answers

[2P-3.) ^2+(2P+3)^2​

[2P-3.) ^2+(2P+3)^2