Amanda needs to pay 1440 cedis for purchasing 8 cakes on discounted price.
<h3>
What is Cost Price?</h3>
Cost price is the amount we pay to buy an item at which it is available.
Here,
Selling price of a cake = 200 cedis
Discount because of sale = 10% on each unit.
(Only if 4 cakes purchased at a time)
Amanda purchased 8 cakes
So, Amanda need to pay only 90 percent of the total amount.
Total cost price of 8 cakes for Amanda = (200 X 90%) X 8
= 180 X 8
= 1440
Thus, Amanda needs to pay 1440 cedis for purchasing 8 cakes on discounted price.
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To determine the scale both measurements must be in the same unit, either feet or meters. 1 meter = 3.28084 feet525 meters = 1722.441 feet Scale is 4.2 / 1722.441, or 0.00243839992 1 foot = 0.3048 meters4.2 feet = 1.28016 meters 1.2801 / 525 = 0.0024389992
Hope This Helped :)
Answer:
You multiply or divide by 10 conveniently
Step-by-step explanation:
For the first expression, remember that

Answer:

Step-by-step explanation:
Let the distance be
and the time be
.
It was given that the distance,
, varies directly as the square of the time
, we write the proportional relation,
.
, where
is the constant of variation.
It was also given that,
, when
.




Now the equation of variation becomes;

When,
, 


The object will travel 301865 feet in 55 seconds.