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andre [41]
3 years ago
6

What is the side length b in the triangle below

Mathematics
2 answers:
Zanzabum3 years ago
4 0
12^2 +b^2 = 20^2 because of the Pythagorean theorem
144 + b^2 =400
B^2 =256
B=16
skelet666 [1.2K]3 years ago
3 0

Answer:

Option B : 16

Step-by-step explanation:

Refer the attached file

Given :

In ΔABC , AB = b , BC = 12  , AC= 20

To Find : value of b i.e. Length of AB

Solution:

Since we are given a right angles triangle so we can use Pythagoras theorem i.e.

(Hypotenuse)^{2} =(Perpendicular)^{2} +(Base)^{2}    ---(a)

Now in a given triangle AB is Perpendicular , BC is Base and AC is Hypotenuse.

So, putting values in (a)

(AC)^{2} =(AB)^{2} +(BC)^{2}

(20)^{2} =(b)^{2} +(12)^{2}

400 =(AB)^{2} +144

400-144  =(b)^{2}

256 =(b)^{2}

\sqrt{256} =b

16=b

Thus the value of b is 6

Hence Option B is correct.


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Answer:

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Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
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__________________________________________________

According to the question ,

1) When α (alpha) = d

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2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

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