B) The alcohol level in a burette is 30cm3. If 55 drops of alcohol fall from the burette

A bicycle wheel is rotating at 50 rpm when the cyclist begins to pedal harder, giving the wheel a constant angular acceleration

aleksandr82 [10.1K]

Answer:

3.025 revolutions

Explanation:

To solve this question firstly we need to calculate the time t

Given the angular velocity and the angular acceleration

The time t = angular velocity/angular acceleration

Converting 50rpm to rad/s

= 50 × 2π /60

=1.67 rad/s

t = 1.67/0.46

t =3.63s

The wheel makes 50 revolutions in one minute

Therefore in 3.63s, it will make

3.63 × 50/60

= 181.5/60

=3.025 revolutions

Approximately 3 revolutions

3 0

3 years ago

Read 2 more answers

Coal is an example of kinetic or potential energy

pav-90 [236]

Answer:

Potential energy

Explanation:

4 0

3 years ago

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If an electrical component with a resistance of 53 Q is connected to a 128-V source, how much current flows through the componen

natta225 [31]

Answer:

the current that flows through the component is 2.42 A

Explanation:

Given;

resistance of the electrical component, r = 53 Ω

the voltage of the source, V = 128 V

The current that flows through the component is calculated using Ohm's Law as demonstrated below;

$V = IR\\\\I = \frac{V}{R} = \frac{128 \ V}{53 \ ohms} = 2.42 \ A$

Therefore, the current that flows through the component is 2.42 A

8 0

3 years ago

Where will you find the most kinetic energy? ice or water?

const2013 [10]

Answer:

Water has more kinetic energy because it is liquid, as ice is harder, so it's cells can't move as much.

7 0

3 years ago

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A neutron star is an extremely dense, rapidly spinning object that results from the collapse of a massive star at the end ofits

Westkost [7]

Answer:

(a). The rotational inertia is $5.72\times10^{39}\ kg m^2$

(b). The magnitude of the magnetic torque is $3.20\times10^{35}\ N-m$

Explanation:

Given that,

Mass of neutron $M_{n}= 13M_{s}$

Density of neutron $\rho=4.8\times10^{17}\ kg/m^3$

(a). We need to calculate the rotational inertia

Using formula of rotational inertia for sphere

$I=\dfrac{2}{5}MR^2$ ...(I)

We know that,

$\rho=\dfrac{M}{V}$

Put the value of volume

$\rho=\dfrac{3M_{n}}{4\pi R^3}$

$R^2=(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}$

Put the value of R in equation (I)

$I=\dfrac{2}{5}\times M_{n}\times(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}$

Put the value into the formula

$I=\dfrac{2}{5}\times(13\times2\times10^{30})^{\frac{5}{3}}\times(\dfrac{3}{4\pi\times(4.8\times10^{17})})^{\frac{2}{3}}$

$I=5.72\times10^{39}\ kg m^2$

The rotational inertia is $5.72\times10^{39}\ kg m^2$ .

(b). We need to calculate the magnitude of the magnetic torque

Using formula of torque

$\tau=I\times \alpha$

Put the value into the formula

$\tau=5.72\times10^{39}\times5.6\times10^{-5}$

$\tau=3.20\times10^{35}\ N-m$

The magnitude of the magnetic torque is $3.20\times10^{35}\ N-m$

Hence, (a). The rotational inertia is $5.72\times10^{39}\ kg m^2$

(b). The magnitude of the magnetic torque is $3.20\times10^{35}\ N-m$

4 0

3 years ago