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Allushta [10]
3 years ago
10

The gage pressure of an automobile tire is measured to be 210kPa before a trip and 220kPa after the trip at a location where the

atmospheric pressure is 95kPa. Assuming the volume of the tire remains constant and the air temperature before the trip is 25o C, determine the air temperature in the tire after the trip. (
Physics
1 answer:
Katarina [22]3 years ago
7 0

Answer:

T_{f} = 312.348\,K\,(39.198\,K)

Explanation:

Let assume that gas inside the automobile tire behaves as an ideal gas. Due to the absence of leakages, the number of moles remains constant during the trip. Air temperature can be found by using the following relation:

\frac{P_{o}}{T_{o}}=\frac{P_{f}}{T_{f}}

Final temperature is cleared with the expression:

T_{f} = \frac{P_{f}}{P_{o}}\cdot T_{o}

T_{f} = \frac{220\,kPa}{210\,kPa}\cdot (298.15\,K)

T_{f} = 312.348\,K\,(39.198\,K)

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Fantom [35]

Answer:

A mass of 10 kilograms lifted 10 meters in 5 seconds.

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

Power = \frac {Energy}{time}

But Energy = mgh

Substituting into the equation, we have

Power = \frac {mgh}{time}

Given the following data;

Mass = 10kg

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Time = 5 seconds

We know that acceleration due to gravity is equal to 9.8 m/s²

Power = \frac {10*9.8*10}{5} = 490 Watts

Hence, a mass of 10 kilograms lifted 10 meters in 5 seconds would produce the most power.

6 0
2 years ago
A spherical helium filled balloon (B) with a hanging passenger cage being held by a single vertical cable (C) attached to Earth
Gre4nikov [31]

Answer:

The tension is  T  = 4326.7 \  N

Explanation:

From the question we are told that

   The  total mass is  m  =  200 \  kg

    The  radius is r = 5 \  m

     The  density of air is  \rho_a  =  1.225 \ kg/m^3

Generally the upward  force acting on the balloon is mathematically represented as

        F_N  =   T  + mg

=>     (\rho_a  *  V  *  g ) =   T  + mg

=>   T  =  (\rho_a  * V  *  g   )  - mg

Here V is the volume  of the spherical helium filled balloon which is mathematically represented as

      V  =  \frac{4}{3}  * \pi r^3

=>   V  =  \frac{4}{3}  * 3.142 *(5)^3

=>   V  = 523.67\  m^3

So

    T  = (1.225 *  523.67*  9.8 ) -  200 *  9.8

   T  = 4326.7 \  N

5 0
3 years ago
A spring with a spring constant value of 125 N/m is compressed 12.2 cm by pushing on it with a 215 g block. When the block is re
allsm [11]

Answer:

v = 2.94 m/s

Explanation:

When the spring is compressed, its potential energy is equal to (1/2)kx^2, where k is the spring constant and x is the distance compressed. At this point there is no kinetic energy due to there being no movement, meaning the net energy in the system is (1/2)kx^2.

Once the spring leaves the system, it will be moving at a constant velocity v, if friction is ignored. At this time, its kinetic energy will be (1/2)mv^2. It won't have any spring potential energy, making the net energy (1/2)mv^2.

Because of the conservation of energy, these two values can be set equal to each other, since energy will not be gained or lost while the spring is decompressing. That means

(1/2)kx^2 = (1/2)mv^2

kx^2 = mv^2

v^2 = (kx^2)/m

v = sqrt((kx^2)/m)

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His weight would be 100 N

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5 0
3 years ago
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LuckyWell [14K]

Answer:

240 m

120 m

Explanation:

d = Path difference = 120 m

For destructive interference

Path difference

d=\dfrac{\lambda}{2}\\\Rightarrow \lambda=2d\\\Rightarrow \lambda=2\times 120\\\Rightarrow \lambda=240\ m

The longest wavelength is 240 m

For constructive interference

d=\lambda\\\Rightarrow 120\ m=\lambda

The longest wavelength is 120 m

4 0
3 years ago
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