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Allushta [10]
3 years ago
10

The gage pressure of an automobile tire is measured to be 210kPa before a trip and 220kPa after the trip at a location where the

atmospheric pressure is 95kPa. Assuming the volume of the tire remains constant and the air temperature before the trip is 25o C, determine the air temperature in the tire after the trip. (
Physics
1 answer:
Katarina [22]3 years ago
7 0

Answer:

T_{f} = 312.348\,K\,(39.198\,K)

Explanation:

Let assume that gas inside the automobile tire behaves as an ideal gas. Due to the absence of leakages, the number of moles remains constant during the trip. Air temperature can be found by using the following relation:

\frac{P_{o}}{T_{o}}=\frac{P_{f}}{T_{f}}

Final temperature is cleared with the expression:

T_{f} = \frac{P_{f}}{P_{o}}\cdot T_{o}

T_{f} = \frac{220\,kPa}{210\,kPa}\cdot (298.15\,K)

T_{f} = 312.348\,K\,(39.198\,K)

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Pounds

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A particle leaves the origin with a speed of 3 106 m/s at 38 degrees to the positive x axis. It moves in a uniform electric fiel
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The electric field intensity along the positive y axis E_y, can be given by the formula:

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If the particle is an electron:

E_y = \frac{2 m_e u^2 sin \theta cos \theta}{qx} \\

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If the particle is a proton:

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8 0
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Nutka1998 [239]

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1 Watt

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6 0
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