Answer:
2 sets of possible solutions:
x=3, y = 5
and
x=-1, y = -3
Step-by-step explanation:
Using the graphical method, (see attached)
you can graph both equations and find their intersection points.
From the attached plot, you can see that the graphs intersect at (3,5) and (-1,-3)
Alternatively, you can solve this numerically by solving the following system of equations. You will get the same answer.
y = 2x + 1 ------------------- eq. (1)
y = x² - 4 ------------------- eq. (2)
Answer:
The probability that a student is proficient in mathematics, but not in reading is, 0.10.
The probability that a student is proficient in reading, but not in mathematics is, 0.17
Step-by-step explanation:
Let's define the events:
L: The student is proficient in reading
M: The student is proficient in math
The probabilities are given by:
The probability that a student is proficient in mathematics, but not in reading is, 0.10.
The probability that a student is proficient in reading, but not in mathematics is, 0.17
We can write how will be defined but that's too much work and it's only useful when we are evaluating
with many inputs.
First let's solve for first. As you read through this answer, you'll get the idea of what I'm doing.
Given:
Solving for :
Now we can solve for , since
,
.
Given:
Solving for :
Now we are can solve for . By now you should get the idea why
.
Given:
Solving for :