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andreev551 [17]

4 years ago

8

Find the greatest common factor for pair 18,36

1 answer:

netineya [11]4 years ago

3 0

The GCF of 18 and 36 is 18. To solve this, use the picture attached. After creating the boxes, find a number that both 18 and 36 can be divided by, for example, 9. Now that you have 9, divide both 18 and 36 by 9. That equals 2 and 4. Place the numbers underneath the boxes you made previously and find another number that both 2 and 4 are divisible by. 2 and 4 are both able to be divided into 2. Do 2 divided by 2 and 4 divided by 2. Now you have the numbers 1 and 2. There aren't any numbers that can be divided into 1 and 2, so now you are left with the numbers 9 and 2. Multiply the numbers together to get a GCF of 18. Hope this helped!

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Simplify the expression below.<br> (8^2)^6<br><br> A.) 8^4<br> B.) 8^3<br> C.) 8^12<br> D.) 8^8

blagie [28]

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3 years ago

Match the graph with the correct set of equations for the linear system. Then, classify the system as Consistent and Dependent,

Ivenika [448]

Answer:

Consistent independent

x + y = 0 and -x + y = -8

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<u>Inconsistent</u>: parallel lines, no solutions

<u>Consistent dependent</u>: same line, infinite solutions

<u>Consistent independent</u>: intersects at one point, one solution

Therefore, the pair of lines are Consistent independent

From inspection of the diagram:

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2 years ago

Consider the expression below. Assume the variable m represents an integer. 6m(3m + 21) Enter an expression in the box that uses

Monica [59]

Answer:

$(a)\ 6m(3m + 21) = 9(2m^2 + 14m)$

(b) Yes, it is divisible by 9

Step-by-step explanation:

Given

$6m(3m + 21)$

Solving (a): Complete the blanks

$6m(3m + 21) = 9 [\ ]$

Expand the bracket

$6m(3[m + 7]) = 9 [\ ]$

$6m*3(m + 7) = 9 [\ ]$

Express 6m as 2m * 3

$2m*3*3(m + 7) = 9 [\ ]$

$2m*9(m + 7) = 9 [\ ]$

Rewrite as:

$9 * 2m(m + 7) = 9 [\ ]$

Multiply the bracket by 2m

$9 * (2m^2 + 14m) = 9 [\ ]$

Divide both sides by 9

$2m^2 + 14m = [\ ]$

<em>Hence, the bracket will be filled with: </em> $2m^2 + 14m$ <em></em>

<em>So:</em>

$6m(3m + 21) = 9(2m^2 + 14m)$

Solving (b): Is $6m(3m + 21)$ divisible by 9?

In (a), we have:

$6m(3m + 21) = 9(2m^2 + 14m)$

The leading factor "9" implies that the expression is divisible by 9

4 0

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