Question

ABCD is a rhombus AC = 5.5 cm and BD = 4 cm. what is the area of the rhombus

Answer 1

Answer:

The area of rhombus ABCD is 11 cm².

Step-by-step explanation:

Given information: ABCD is a rhombus AC = 5.5 cm and BD = 4 cm.

AC and BD are two diagonals of rhombus.

The area of a rhombus is

$A=\frac{1}{2}\times d_1\times d_2$

$A=\frac{1}{2}\times AC\times BD$

$A=\frac{1}{2}\times 5.5\times 4$

$A=11$

Therefore the area of rhombus ABCD is 11 cm².

Answer 2

A = 11. Hope this helped!