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mariarad [96]
4 years ago
14

Please help.......!!!!!!!!!!

Mathematics
2 answers:
Inessa05 [86]4 years ago
7 0

Answer:

20 feet

Step-by-step explanation:

(Took the test and got this right)

If my answer qualifies please mark brainliest!

Studentka2010 [4]4 years ago
3 0

Answer:

20 feef

Step-by-step explanation:

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Write a percent that has a value between the two decimals 0.4 and 0.5
Juliette [100K]
A percent would be 0.45 
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4 years ago
Paulie ordered 250 pens and 250 pencils to sell for a theatre club fundraiser. The pens cost 11 cents more than the pencils. If
Korolek [52]
Remember that cents has a decimal when put in an equation.
250(x + 11) + 250x = 4250
250x + 2750 + 250x = 4250
500x + 2750 = 4250
500x = 1500
x = 3 cents (pencils)
x+11 = 14 cents (pens)
4 0
4 years ago
How do solve for x in 50=-10(x+10)​
Svetllana [295]

Answer:

x=-15

Step-by-step explanation:

50=-10(x+10)

Distribute 10: 50=-10x-100

Add 100 to both sides: 100+50=-10x-100+100

150=-10x

Simplify: 150/-10=-10x/-10

x=-15

4 0
3 years ago
Emilio cay type 850 words in 17 minutes. How many words can he type in one hour?
Nutka1998 [239]

Answer:

3,000 words

Step-by-step explanation:

we know that

Emilio cay type 850 words in 17 minutes

Remember that

1\ h=60\ min

so

using proportion

Find out how many words can Emilio type in 60 minutes (one hour)

Let

x ---> the number of words

\frac{850}{17}\ \frac{words}{minutes} =\frac{x}{60}\ \frac{words}{minutes}\\\\x=60(850)/17\\\\x= 3,000\ words

3 0
4 years ago
You flip a coin and then roll a 6-sided number cube (a die).
expeople1 [14]

Answer:

a)  No, it does not matter whether you roll the die or flip the coin first, as these two events are <u>independent</u> of each other, which means they do not affect each other.

b) Yes.

  • Let event 1 be flipping a coin and event 2 be rolling a die.
  • Let event 1 be rolling a die and event 2 be flipping a coin.

The likelihood that any outcome will occur will not change, as the events are independent.

c) see attached

d)   12 outcomes  (H = head, T = tail, numbers represent the value of the die)

H 1           T 1

H 2          T 2

H 3          T 3

H 4          T 4

H 5          T 5

H 6          T 6

e)  

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

\implies \sf P(even)=\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{6}=\dfrac{3}{6}=\dfrac{1}{2}

\implies \sf P(head)=\dfrac{1}{2}

\implies \sf P(even)\:and\:P(head)=\dfrac{1}{2} \times \dfrac{1}{2}=\dfrac{1}{4}

6 0
2 years ago
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