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zvonat [6]
3 years ago
15

Suppose that X ∼ Geom(p) and Y ∼ Geom(r) are independent. Find the probability P (X < Y ).

Mathematics
1 answer:
Murrr4er [49]3 years ago
4 0

X,Y have joint density

f_{X,Y}(x,y)=f_X(x)f_Y(y)=\begin{cases}pr(1-p)^x(1-r)^y&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}

We can find P(X by integrating the joint density over the region in \Bbb R^2 where x in the first quadrant, i.e. above the line y=x:P(X

using the fact that

a^n=e^{n\ln a}\implies\displaystyle\int a^n\,\mathrm dn=\frac1{\ln a}e^{n\ln a}+C=\frac1{\ln a}a^n+C

Then using the same property,

P(X

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A<br> 19 = 548 and a<br> 33 = 968<br> Find a<br> 27
s2008m [1.1K]

Answer:

The value of a₂₇ is 788

Step-by-step explanation:

a₁₉ = 548

a₃₃ = 968

Now,

a₁₉ = 548 can be written as

a + 18d = 548 ...(1) and

a₃₃ = 968 can be written as

a + 32d = 968 ...(2)

Now, from equation (2) we get,

a + 32d = 968

a + 18d + 14d = 968

548 + 14d = 968 (.°. <u>a + 18d = 548</u>)

14d = 968 - 548

14d = 420

d = 420 ÷ 14

d = 30

Now, for the value of a put the value of d = 30 in equation (1)

a + 18d = 548

a + 18(30) = 548

a + 540 = 548

a = 548 - 540

a = 8

Now, For a₂₇

a₂₇ = a + 26d

a₂₇ = 8 + 26(30)

a₂₇ = 8 + 780

a₂₇ = 788

Thus, The value of a₂₇ is 788

<u>-TheUnknownScientist</u>

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Which equation is represented by the graph below
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Answer:

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Step-by-step explanation:

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Answer:

alright all you need to do is Use the slope-intercept form to find the slope and y-intercept

So the Answer to the question is

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Step-by-step explanation:


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