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nataly862011 [7]
3 years ago
6

A cylindrical swimming pool has a diameter of 20 feet and a height of 3.5 feet. How many gallons of water can the pool contain?

Round your answer to the nearest whole number. (1 ft3 ≈ 7.5 gal)
Mathematics
1 answer:
kvasek [131]3 years ago
6 0

Answer:

The swimming pool will contain approx 8243\ gal of water.

Step-by-step explanation:

Given the swimming pool is in a cylindrical shape.

And the dimensions are 20\ feet diameter with a height of 3.5\ feet.

Also, 1\ ft^3 =7.5\ gal

First, we will find the volume of the swimming pool.

The swimming pool is in cylindrical shape.

So, the volume would be \pi r^2h

The height (h) is given as 3.5\ feet. To calculate radius (r) we will divide the diameter by two.

The radius of the cylinder would be \frac{20}{2}=10\ feet

Plug these values in the formula we get,

\pi r^2h\\=\pi\times 10^2\times 3.5\\=3.14\times 100\times 3.5\\=1099\ ft^3

Now, it is given 1\ ft^3 =7.5\ gal

So, 1099\ ft^3 =1099\times 7.5\ gal=8242.5\ gal

The swimming pool will contain approx 8243\ gal of water.

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