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nataly862011 [7]

3 years ago

6

A cylindrical swimming pool has a diameter of 20 feet and a height of 3.5 feet. How many gallons of water can the pool contain?

Round your answer to the nearest whole number. (1 ft3 ≈ 7.5 gal)

1 answer:

kvasek [131]3 years ago

6 0

Answer:

The swimming pool will contain approx $8243\ gal$ of water.

Step-by-step explanation:

Given the swimming pool is in a cylindrical shape.

And the dimensions are $20\ feet$ diameter with a height of $3.5\ feet.$

Also, $1\ ft^3 =7.5\ gal$

First, we will find the volume of the swimming pool.

The swimming pool is in cylindrical shape.

So, the volume would be $\pi r^2h$

The height $(h)$ is given as $3.5\ feet.$ To calculate radius $(r)$ we will divide the diameter by two.

The radius of the cylinder would be $\frac{20}{2}=10\ feet$

Plug these values in the formula we get,

$\pi r^2h\\=\pi\times 10^2\times 3.5\\=3.14\times 100\times 3.5\\=1099\ ft^3$

Now, it is given $1\ ft^3 =7.5\ gal$

So, $1099\ ft^3 =1099\times 7.5\ gal=8242.5\ gal$

The swimming pool will contain approx $8243\ gal$ of water.

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