Find the area of an equilateral triangle with radius 5√3 m. Leave your answer in simplest radical form.

2 answers:

6 0

In an equilateral triangle the radius of inscribed circle is equal to
$r= \frac{a \sqrt{3} }{6}$ , so
$5 \sqrt{3} = \frac{a \sqrt{3} }{6}$ and
$a=30$ .
The area of this equilateral triangle is $A= \frac{a^2 \sqrt{3} }{4} =\frac{30^2\cdot \sqrt{3} }{4}=225 \sqrt{3}$ square units.

alina1380 [7]3 years ago

3 0

Answer:

$\frac{225}{4}$ $\sqrt{3}$ $m^{2}$

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