Answer:
There were 140 tickets sold that cost $15 and 160 tickets sold that cost $20.
Step-by-step explanation:
To solve this problem, we should create a system of equations. Let's let the variable x represent the number of $15 tickets sold and let the variable y represent the number of $20 tickets sold. Using these variables, we can make the following equations:
x + y = 300
15x + 20y = 5300
To solve this equation, we can use substitution. Our first step in this case is solving the first equation for one variable; let's choose x.
x = 300 - y
Now, we can substitute this value for x into the second equation.
15(300-y) + 20y = 5300
Next we can distribute through the parentheses on the left side of the equation.
4500 - 15y + 20y = 5300
We can combine like terms on the left side of the equation to simplify.
4500 + 5y = 5300
We should then subtract 4500 from both sides of the equation.
5y = 800
Finally, we can divide both sides of the equation by 5.
y = 160
To solve for x, we can substitute this value for y into either of our original equations, but we should probably choose the first one for simplicity.
x + y = 300
x + 160 = 300
x = 140
Therefore, x = 140 and y = 160; this means that 140 $15 tickets were sold and 160 $20 tickets were sold.
Hope this helps!
