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bulgar [2K]
3 years ago
13

One of the wagers in roulette is to bet that the ball will stop on a number that is a multiple of 3. (Both 0 and 00 are not incl

uded.) If the ball stops on such a number, the player wins double the amount bet. If a player bets $2, compute the player's expectation.
Mathematics
1 answer:
Arlecino [84]3 years ago
8 0

Answer:

The players expectation is -0.1052

Step-by-step explanation:

Consider the Roulette numbers to from 1-36, also the two green zeroes 0 and 00,

Thus, there are 38 places on which the ball can land.

On first 36 numbers, 12 of them are divisible by 3. Also there are 26 numbers which are not divisible by 3.

The probability of a wager winning is: 12/38 or 6/19

Now the probability of a wager to loss is: 26/38 or 13/19

So for a 6/19 chance of winning $4 and a 13/19 chance of losing $2.

Therefore, the expected outcome is:

4 × 6/19 + -2 × 13/19 = 1.2632 - 1.3684 = -0.1052

The expected value comes up with a negative sign. Hence, he will lose money.

The players expectation is -0.1052

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BC = x + 14, AB = x + 10, AC = 22
irinina [24]

ab = x + 10 \\  bc = x  + 14 \\ ac = 22  \\ (x + 10) + (x + 14) = 22 \\ x + x + 10 + 14 = 22 \\ 2x + 24 = 22 \\ 2x = 22 - 24  \\ 2x =  - 2 \\ x =  \frac{ -2}{2}  \\ x =  - 1

4 0
3 years ago
Translate then Solve for the variable:
Sergeu [11.5K]

The linear equation will be 2x + 10 = 5(x - 6). Then the value of the variable x will be 23.33.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Translate then Solve for the variable:

The sum of two times a number and 10 is five times the difference between a number and six.

Let the number be x.

Then the equation will be

2x + 10 = 5(x - 6)

Then the value of x will be

2x + 10 = 5x - 60

5x - 2x = 60 + 10

      3x = 70

        x = 23.33

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ1

8 0
2 years ago
(Essay Question 7 Points)
Irina18 [472]

Well I don't know.
Let's think about it:

-- There are 6 possibilities for each role.
    So 36 possibilities for 2 rolls.
    Doesn't take us anywhere.

New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !

-- The die has 3 odds and 3 evens.

-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4

I'm sure this is it.  I'm a little shaky on how to combine those 2 probs.

Ah hah ! 
Try this:

Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .

That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .

So the probability of 2 rolls that sum to an even number is 1/2 = 50% .

Is this reasonable, or sleazy ?


4 0
3 years ago
What is the redosed fraction for 3897/1000
Nadusha1986 [10]

Answer:

3000.897

Step-by-step explanation:

3 0
3 years ago
Simplify the following:
aivan3 [116]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
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