Hey there!
A dolphin swims 40 miles per hour. In feet, this is 211,200 because there’s 5,280 feet in a mile. Divide 211,200 by 60 to get 3,520. The dolphin travels 3520 feet a minute.
I hope this helps!
Answer:
9.72
Step-by-step explanation:
s1 = 10.6383 ; s2 = 5.21289
x1 = 147.583 ; x2 = 136.417
n1 = 12 ; n2 = 12
df1 = n1 - 1 = 12 - 1 = 11
df2 = n2 - 1 = 12 - 1 = 11
The test statistic :
(x1 - x2) / sqrt[(sp²/n1 + sp²/n2)]
Pooled variance = Sp² = (df1*s1² + df2*s2²) ÷ (n1 + n2 - 2)
Sp² = ((11*10.6383) + (11*5.21289)) / 22 = 7.926
Test statistic, T* :
(147.583 - 136.417) / √(7.926 * (1/12 + 1/12))
11.166 / √(7.926 * (1/6)
11.166 / √1.321
11.166 / 1.1493476
T* = 9.7150766
Test statistic = 9.72
The answer is 1/64 because you do 3/8 ÷ 24/1 then you
flip and it will be 3/8 ÷ 1/24 you can cross cancel
24 go's into three 8 times so the answer is 1/64s.
Hope I helped!
=)
5914 1404 393
Answer:
A) 1.3×10^37 ergs
B) 1.435×10^3 mm
Step-by-step explanation:
A) The amount of energy will be the product of the energy rate and time:
(3.9×10^33 ergs/s)×(3.25×10^3 s) =12.675×10^(33+3) ergs
= 1.2675×10^(1+36) ergs
= 1.2675×10^37 ergs ≈ 1.3×10^37 ergs
The mantissa of the result is the product 3.9×3.25, adjusted to have one digit left of the decimal point. The exponent of the result is the sum of the exponents of the factors, adjusted by 1 to match the adjustment in the mantissa.
The final value should be rounded to 2 significant figures, reflecting the precision of the sun's energy production.
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B) A millimeter is a small fraction of an inch. 10^-3 mm is a small fraction of the width of a human hair, so 1.435×10^-3 mm is not a reasonable estimate of the distance between railroad tracks.
On the other hand, 1.435×10^3 mm is 1.435 m, almost 56.5 inches. This is a much more reasonable measurement of the distance between railroad rails.
1.435×10^3 mm is more reasonable
