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MakcuM [25]
3 years ago
5

A french class has a total of 25 student.The number of males is 7 more than the number of females how many males and how many fe

males are in the class?
Mathematics
2 answers:
Naddik [55]3 years ago
4 0

Answer:

16 males and 9 females.

Step-by-step explanation:

If you subtract 7 from 25 you get 18. If you split 18 in half you get 9. Which means if you add 7 to 9 you get the number of males, which leaves you with 9 students left so the rest are females.

Lady_Fox [76]3 years ago
3 0

Answer:

16 males and 9 females

Step-by-step explanation:

To solve this we can use a system of equations.

Let's start by naming the number of females x.

The number of males would then be y.

<u>Using these variables, we can set up 2 equations using info provided:</u>

A french class has a total of 25 students, -> x+y=25

The number of males is 7 more than the number of females -> x+7=y

Use substitution to solve.

<u>From the second equation:</u>

x+7=y

Subtract 7 from both sides.

x=y-7

Substitute that into the first equation.

x+y=25

y-7+y=25

Combine like terms.

2y-7=25

Add 7 to both sides.

2y=32

Divide both sides by 2.

y=16

Substitute y=16 into equation 2.

x+7=y

x+7=16

Subtract 7 from both sides.

x=9

Therefore, there are 16 males and 9 females in the french class.

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on February 18th from 9 a.m. until 2 p.m. the temperature goes from -14 degrees Fahrenheit to 36 degrees Fahrenheit what is the
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3 years ago
Solve each system by elemination, 4x+8y=20 and -4x+2y=-30
ludmilkaskok [199]
The sum of the left side of these two equations is equal to the same of the right side is these two equations
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5 0
3 years ago
Two more than a number is less than 14. 2 + n less-than-or-equal-to 14 2 + n less-than 14 2 + n greater-than-or-equal-to 14 2 +
statuscvo [17]

Answer:

x+2 < 14 | -2

x < 12

2+n <= 14 | -2

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2+n < 14 | -2

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8 0
3 years ago
The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe
juin [17]

The height of container is 8 feet

<em><u>Solution:</u></em>

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

<em><u>The volume of container is given as:</u></em>

v = length \times width \times height

Given that volume of the container is 216 cubic feet

216 = l \times w \times h

Substitute eqn 1 and eqn 2 in above formula

216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0

Solve by factoring

(h-8)(h^2+4h+27) = 0

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

h - 8 = 0\\\\h = 8

Also,

h^2+4h+27 = 0

Solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}

h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}

Therefore, on solving we get,

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

<em><u>Thus solutions of "h" are:</u></em>

h = 8

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0
3 years ago
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