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Vesna [10]
3 years ago
14

How would you solve this? Bc I don’t know which operation to use

Mathematics
1 answer:
emmainna [20.7K]3 years ago
4 0

Answer:

W = field width = 48 ft

Step-by-step explanation:

Review:  the formula for Perimeter of a rectangle is P = 2W + 2L.

Here we're told that the Perimeter is 168 ft.  Therefore:

168 ft = 2L + 2W.  But we are also told that W = 36 ft.  Then:

168 ft = 2L + 2(36 ft) = 2L + 72 ft.

Subtracting 72 ft from both sides, we get 2L = 96, which tells us that:

L = 48 ft.

The field is 48 ft long.

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(Volume for a rectangular shape is length x width x height)

We can split up this 3D composite figure into two main parts (as shown in the picture I attached), and find each part’s volume before adding them together for the total volume.

Cube —> 5x5x5 —> 25x5 = 125 in^3

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7 0
3 years ago
A Pew Research Center report on gamers and gaming estimated that 49% of U.S. adults play video games on a computer, TV, game con
Veseljchak [2.6K]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have that:

  • 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.
  • 49% out of 2001 U.S. adults play video games, hence \pi = 0.49, n = 2001.

The lower bound of the interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 - 1.96\sqrt{\frac{0.49(0.51)}{2001}} = 0.4681

The upper bound of the interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 + 1.96\sqrt{\frac{0.49(0.51)}{2001}} = 0.5119

The 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.

To learn more about the z-distribution, you can take a look at brainly.com/question/25730047

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