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svetlana [45]
3 years ago
14

Hey please help me here!

Mathematics
1 answer:
Readme [11.4K]3 years ago
5 0
The options have to either be B or C.
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Use the rules of exponents to evaluate or simplify. Write without negative exponents.
Zielflug [23.3K]

Answer:

  • 2

Step-by-step explanation:

  • (\frac{1}{4})^{-1/2} =
  • (\frac{1}{\frac{1}{4} })^{1/2} =
  • 4^{1/2} =
  • 2^{2*1/2} =
  • 2^{1} =
  • 2

<u>Properties used</u>

  • a^{-b}  = (\frac{1}{a} )^b
  • (a^{b} )^c = a^{bc}
3 0
3 years ago
A bird traveled 4 miles north before stopping to rest. The bird then flew 2,640 yards south in search of food. Finally, it flew
ra1l [238]
7 and 1/2 mile because 2,640=1.5 miles
4-1.5=2.5+5=7.5
8 0
3 years ago
22 divided by y equals -2?
aleksley [76]
22 divided by -11 = -2
5 0
4 years ago
Read 2 more answers
Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab
Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx

If f(x)=x^2, then

f'(x)=2x

and

b=0\\ \\a=2

Therefore,

SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx

Apply substitution

x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du

Then

SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du

Now

\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))

Hence,

SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}

3 0
3 years ago
X-2y=12 what would be the coordinates for y
kykrilka [37]
24 :) Hope this helps!
8 0
3 years ago
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